使用NetComm dll發送屏幕截圖到主機

Question

我正在使用NetComm DLL來處理多用戶。我的問題是，當我發送文本的工作正常，但當我採取截圖時，它不工作。 我的客戶端代碼是

ms = new MemoryStream(); 
      bmpScreenshot.Save(ms, ImageFormat.Png); 
      byte[] buffer; 
      buffer =imageToByteArray(bmpScreenshot); 
      client.SendData(buffer); 

這轉換圖像以字節數組的函數是：

public byte[] imageToByteArray(System.Drawing.Image imageIn) 
     { 
      MemoryStream ms = new MemoryStream(); 
      imageIn.Save(ms, System.Drawing.Imaging.ImageFormat.Gif); 
      return ms.ToArray(); 
     } 

而且在接收端我處理是這樣的：

Stream stream = new MemoryStream(Data); // Data is byte array 
    pictureBox1.Image = Image.FromStream(stream); 
    pictureBox1.Refresh(); 

收到後，我在圖片框中顯示圖像。

使用NetComm的DLL我只能發送和接收bytearray格式的數據。

NetComm dll爲我提供了使用其ID從客戶端與另一個客戶端進行通信的功能。當服務器啓動時，它等待客戶端，一旦客戶端連接，它開始以abc1，abc2，abc3等方式給予他們id。當abc1想要與abc3通信時，只需輸入abc3作爲id而不是IP，併發送該消息應發送給abc3的消息。

正如你可以看到有連接到服務器的兩個客戶端，並都得到類似jack1和jack2的ID。現在如果他們想互相溝通，他們只需輸入相應的ID併發送消息。

Answer 1

我試圖做一個簡單的客戶端 - >客戶端消息發送，這將是一個位圖。當我嘗試將它與不同的端口一起使用時，我遇到了問題，但端口被阻塞了，這就是問題所在。檢查一下。檢查代碼，看看是否有幫助：

namespace CommTest 
{ 
    public partial class Form1 : Form 
    { 
     public Form1() 
     { 
      InitializeComponent(); 
     } 

     NetComm.Host host = new NetComm.Host(10010); 
     NetComm.Client client1 = new NetComm.Client(); 
     NetComm.Client client2 = new NetComm.Client(); 

     private void Form1_Load(object sender, EventArgs e) 
     { 
      host.StartConnection(); 
      client1.Connect("localhost", 10010, "Jack"); 
      client2.Connect("localhost", 10010, "Jack2"); 
      client2.DataReceived += client2_DataReceived; 
      client1.SendData(imageToByteArray(Image.FromFile("Bitmap1.bmp")), "Jack2"); 
     } 

     void client2_DataReceived(byte[] Data, string ID) 
     { 
      Stream stream = new MemoryStream(Data); // Data is byte array 
      pictureBox1.Image = Image.FromStream(stream); 
      // pictureBox1.Refresh(); works without it 
     } 

     public byte[] imageToByteArray(Image imageIn) 
     { 
      MemoryStream ms = new MemoryStream(); 
      imageIn.Save(ms, ImageFormat.Gif); 
      return ms.ToArray(); 
     } 

     private void Form1_FormClosed(object sender, FormClosedEventArgs e) 
     { 
      host.CloseConnection(); 
     } 
    } 
} 

Answer 2

完整的服務器/客戶端實現可能是這樣的。您不需要實現2個不同的客戶端程序，但客戶端和服務器應該不同。這是一個例子，如何利用廣播>

的Program.cs

static class Program 
{ 
    /// <summary> 
    /// The main entry point for the application. 
    /// </summary> 
    [STAThread] 
    static void Main(string[] argv) 
    { 
     Application.EnableVisualStyles(); 
     Application.SetCompatibleTextRenderingDefault(false); 
     // if You run the program like "CommTest.exe 10010", than it will be host. 
     // if You run it like "CommTest.exe localhost 10010", than it will be client connecting to localhost. 
     if (argv.Length == 1) 
     { 
      Application.Run(new Form2(new Host(int.Parse(argv[0])))); 
     } 
     else 
     { 
      Application.Run(new Form1(new Client(argv[0], int.Parse(argv[1])))); 
     } 
    } 
} 

Form1.cs的

public partial class Form1 : Form 
{ 
    public Form1(NetComm.Client client) 
    { 
     _client = client; 
     InitializeComponent(); 
    } 

    // there is a button to broadcast picture on the client. 
    private void Button1_Click(object sender, EventArgs e) 
    { 
     // update the image that should be broadcasted as You like. 
     _client.SendData(imageToByteArray(Image.FromFile("Bitmap1.bmp"))); 
    } 

    NetComm.Client _client; 

    private void Form1_Load(object sender, EventArgs e) 
    { 
     button1.Click += Button1_Click; 
     _client.DataReceived += client_DataReceived; 
    } 

    void client_DataReceived(byte[] Data, string ID) 
    { 
     Stream stream = new MemoryStream(Data); // Data is byte array 
     pictureBox1.Image = Image.FromStream(stream); 
    } 

    public byte[] imageToByteArray(Image imageIn) 
    { 
     MemoryStream ms = new MemoryStream(); 
     imageIn.Save(ms, ImageFormat.Gif); 
     return ms.ToArray(); 
    } 

    private void Form1_FormClosed(object sender, FormClosedEventArgs e) 
    { 
     _client.Disconnect(); 
    } 
} 

Client.cs

class Client: NetComm.Client 
{ 
    public Client(string ip, int port):base() 
    { 
     // in this example, the ids are not considered. In a real world situation Clients should send a first message to the host, 
     // and host should reply with a free id. That id should be in the place of Guid.NewGuid().ToString() 
     Connect(ip, port, Guid.NewGuid().ToString()); 
    } 
} 

Form2.cs

public partial class Form2 : Form 
{ 
    public Form2(NetComm.Host host) 
    { 
     _host = host; 
     InitializeComponent(); 
    } 

    NetComm.Host _host; 

    private void Form2_Load(object sender, EventArgs e) 
    { 
     button1.Click += Button1_Click; 
    } 

    // there is a button to close the connection on the host form. 
    private void Button1_Click(object sender, EventArgs e) 
    { 
     _host.CloseConnection(); 
    } 

    private void Form2_FormClosed(object sender, FormClosedEventArgs e) 
    { 
     _host.CloseConnection(); 
    } 
} 

個

Host.cs

class Host: NetComm.Host 
{ 
    public Host(int port):base(port) 
    { 
     StartConnection(); 
     DataReceived += Host_DataReceived; 
    } 

    void Host_DataReceived(string ID, byte[] Data) 
    { 
     Brodcast(Data); 
    } 
}