將整數轉換爲二進制返回錯誤的值

Question

我創建了一個數字轉換器，我需要將整數轉換爲二進制。當我試圖轉換整數12。它給我一個值0 0 0 0 0 1 0 0而不是0 0 0 0 1 1 0 0。

代碼：

number = int(input("Enter a integer between 255 and 0: ")) 
    if (number > 255) or (number < 0): 
     print("Please input less than 255!!!") 
    else: 
     a = False 

     for myCounter in range (8): 

      if (number % 2 == 1):#if remainder is equal to 1 
       myResult = ' 1 ' + myResult#add '1' character to the string 

      else: 
       (number % 2 == 0)#if input has no remainder 
       myResult = ' 0 ' + myResult#add '0' character to the string 

      number = number/2 

     print("Binary equivalent is: %s" %myResult) 

我如何四捨五入的0.5到1使用ROUND_HALF_UP？輸出如下。

任何幫助將不勝感激謝謝！

Answer 1

該代碼在Python 2.7中正常工作。對於Python 3.x嘗試更換number = number/2到number=number//2

number = 12 
a = False 
myResult = '' 
for myCounter in range (8): 

    if (number % 2 == 1):#if remainder is equal to 1 
     myResult = ' 1 ' + myResult#add '1' character to the string 

    else: 
     (number % 2 == 0)#if input has no remainder 
     myResult = ' 0 ' + myResult#add '0' character to the string 

    number = number // 2 

print("Binary equivalent is: %s" %myResult)