SQL多計數和JOIN

Question

我試圖做這樣的事情：

User_guid | Post Message | Discussion board | Total | 

1 | 300 | 25 | 325 | 

2 | 15 | 185 | 200 | 

3 | 100 | 203 | 303 | 

，但我不知道怎麼辦。

我有發帖子的結果與此查詢：

SELECT COUNT(*) as 'Quantidade' , users_entity.name , users_entity.username 
FROM river 
JOIN users_entity 
ON river.subject_guid = users_entity.guid 
AND river.action_type = 'create' 
AND river.view = 'river/object/thewire/create' 
GROUP BY river.subject_guid ORDER BY 'Quantidade' DESC 

，我有這個查詢的結果的討論：

SELECT COUNT(*) as 'Quantidade' , users_entity.name , users_entity.username 
FROM river 
JOIN users_entity 
ON river.subject_guid = users_entity.guid 
AND river.action_type = 'reply' 
GROUP BY river.subject_guid ORDER BY 'Quantidade' DESC 

但我不知道如何加入這些結果users_entity表的行。總的互動應該是帖子信息和討論板值的總和。有人可以幫助我嗎？謝謝。

Answer 1

很難說沒有表結構和樣本數據（這就是爲什麼你得到了下來票），但你可能需要的東西是這樣的：

SELECT 
    users_entity.name, 
    users_entity.username, 
    COUNT(CASE WHEN river.action_type = 'create' AND river.view = 'river/object/thewire/create' THEN 1 END) AS Post_Message, 
    COUNT(CASE WHEN river.action_type = 'reply' THEN 1 END) AS Discussion_Board 
FROM river 
JOIN users_entity ON users_entity.guid = river.subject_guid 
GROUP BY 
    users_entity.name, 
    users_entity.username 
ORDER BY ??? 

我不確定您想要哪個值ORDER BY與合併查詢。

Answer 2

或許這對你的作品：

SELECT data1.username, data1.count1, data2.count2, data1.count1+data2.count2 from 
(
SELECT COUNT(*) as 'count1' , users_entity.name , users_entity.username 
FROM river 
JOIN users_entity 
ON river.subject_guid = users_entity.guid 
AND river.action_type = 'create' 
AND river.view = 'river/object/thewire/create' 
GROUP BY river.subject_guid ORDER BY 'Quantidade' DESC 
) data1, 
(
SELECT COUNT(*) as 'count2' , users_entity.name , users_entity.username 
FROM river 
JOIN users_entity 
ON river.subject_guid = users_entity.guid 
AND river.action_type = 'reply' 
GROUP BY river.subject_guid ORDER BY 'Quantidade' DESC) data2 where data1.username = data2.username 

Answer 3

你可以試着加入這樣

SELECT river_create.Quantidade AS create_q, river_reply.Quantidade AS reply_q, river_create.full_name, river_create.u_name, river_create.user_id 
    FROM 
    (SELECT COUNT(*) as 'Quantidade' , users_entity.name AS full_name, users_entity.username AS u_name, users_entity.guid AS user_id 
     FROM river 
     JOIN users_entity 
     ON river.subject_guid = users_entity.guid 
     AND river.action_type = 'create' 
     AND river.view = 'river/object/thewire/create' 
     GROUP BY river.subject_guid ORDER BY 'Quantidade' DESC) AS river_create 
    INNER JOIN 
    (SELECT COUNT(*) as 'Quantidade' , users_entity.name , users_entity.username, users_entity.guid as reply_user_id 
     FROM river 
     JOIN users_entity 
     ON river.subject_guid = users_entity.guid 
     AND river.action_type = 'reply' 
     GROUP BY river.subject_guid ORDER BY 'Quantidade' DESC) AS river_reply 
ON river_create.user_id = river_reply.reply_user_id