在Python中計算滿足條件的所有條件

Question

是否有一種方法可以在速記嵌套循環中添加滿足條件的所有條件？我下面嘗試失敗：

count += 1 if n == fresh for n in buckets['actual'][e] else 0 

Answer 1

使用sum與發電機的表達：

sum(n == fresh for n in buckets['actual'][e]) 

爲True == 1和False == 0，所以不需要else。

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相關閱讀：Is it Pythonic to use bools as ints? ，Is False == 0 and True == 1 in Python an implementation detail or is it guaranteed by the language?

Answer 2

使用sum()功能：

sum(1 if n == fresh else 0 for n in buckets['actual'][e]) 

或：

sum(1 for n in buckets['actual'][e] if n == fresh)