用兩個無符號的16位整數表示一個無符號的32位值

Question

如何在Swift中用UInt16兩個數字表示UInt32，反之亦然？

例如，UInt32 65536應是（UINT16）1和（UINT16）65535，和（UINT16）0和（UINT16）65533結合（UInt32的）65533

Answer 1

簡單的按位運算

var number1: UInt16 = 1 
var number2: UInt16 = 65535 
let number: UInt32 = UInt32(number1) << 16 | UInt32(number2) 

number1 = UInt16(number >> 16) 
number2 = UInt16(number & 0xFFFF) 

Answer 2

func toInt16(value:UInt32)->(UInt16,UInt16){ 
    return (UInt16(value >> 16),UInt16(value & UInt32(UInt16.max))) 
} 

func toInt32(value1:UInt16,value2:UInt16)->UInt32{ 
    return (UInt32(value1) << 16 | UInt32(value2)) 
}