php
  • cell
  • 2014-03-05 55 views 0 likes 
    0

    顯示2個變量,我想在一個單元格顯示兩個畫面變量如何在一個單元格的Mysql

    http://i.imgur.com/9ZuRhnD.gif

    $result = mysqli_query($query) 
        or die(mysql_error()); 
    if (mysqli_num_rows($result) > 0) { 
    echo "<table border='0' style='border-collapse: collapse;border-color: white;'>"; 
    $i = 0; 
    while($row = mysqli_fetch_array($result)){ 
        $Limg = $row['Limg']; 
        $Limgt = $row['Limgt']; 
          if ($i==0) { 
             echo "<tr>\n"; 
             } 
          echo "<td align='center' width='140'>" . "<img src=\"{$row['Limgt']}\">" ."</td>"; 
          echo "<td align='center' width='40'>" . "<img src=\"{$row['Limg']}\">" ."</td>"; 
          $i++; 
          if ($i == $items) { 
               echo "</tr>\n"; 
               $i = 0; 
               } 
    } 
    echo '</table>'; 
    }else { 
        echo 'no records found'; 
    } 
    ?> 
    

    我缺少什麼

    +0

    兩個圖像應分兩個TR,那麼你將有你的預期輸出 –

    回答

    0

    你把他們每個在他們自己的細胞() - 試試這個:

    $result = mysqli_query($query) 
        or die(mysql_error()); 
    if (mysqli_num_rows($result) > 0) { 
    echo "<table border='0' style='border-collapse: collapse;border-color: white;'>"; 
    $i = 0; 
    while($row = mysqli_fetch_array($result)){ 
        $Limg = $row['Limg']; 
        $Limgt = $row['Limgt']; 
          if ($i==0) { 
             echo "<tr>\n<td>"; 
             } 
          echo "<img src=\"{$row['Limgt']}\">"; 
          echo "<img src=\"{$row['Limg']}\">"; 
          $i++; 
          if ($i == $items) { 
               echo "</td></tr>\n"; 
               $i = 0; 
               } 
    } 
    echo '</table>'; 
    }else { 
        echo 'no records found'; 
    } 
    ?> 
    
    +0

    這工作的感謝 – user3375733

    0

    你正在使他們兩個達陣,所以你必須讓他們在一個TD像

    echo "<td align='center' width='140'> 
          <img src=\"{$row['Limgt']}\"> 
          <img src=\"{$row['Limg']}\"> 
         </td>"; 
    
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