我在下面的代碼中解析xml在dom中的空白屏幕android

我試圖在DOM中解析XML時出現空白屏幕。我沒有在清單中設置任何權限...請幫助！我有我的清單權利。我在下面的代碼中解析xml在dom中的空白屏幕android

其正常工作.....

package com.example.techgeek; 

import java.io.InputStream; 
import java.net.URL; 
import java.util.ArrayList; 
import javax.xml.parsers.DocumentBuilder; 
import javax.xml.parsers.DocumentBuilderFactory; 
import android.os.*; 
import android.app.Activity; 
import android.app.ListActivity; 
import android.content.Intent; 
import org.w3c.dom.Document; 
import org.w3c.dom.Element; 
import org.w3c.dom.Node; 
import org.w3c.dom.NodeList; 
import org.xml.sax.InputSource; 
import org.xml.sax.XMLReader; 
import android.os.Bundle; 
import android.util.Log; 
import android.view.View; 
import android.view.View.OnClickListener; 
import android.widget.*; 

public class second extends ListActivity { 
    String name; 
    public static String pass,pass2; 
    String[] getname=new String[100]; 
    Element element2;Node node;NodeList nList; 
    ArrayList<String> list = new ArrayList<String>(); 
    ArrayList<String> list2 = new ArrayList<String>(); 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     // TODO Auto-generated method stub 
     super.onCreate(savedInstanceState); 
     try { 
      //InputStream is = getAssets().open("file.xml"); 
      URL url = new URL("http://sre.hostoi.com/xml_eg.xml"); 

      DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); 
      DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); 
      //Document doc = dBuilder.parse(is); 
      Document doc = dBuilder.parse(new InputSource(url.openStream())); 
      Element element=doc.getDocumentElement(); 
      element.normalize(); 

      nList = doc.getElementsByTagName("employee"); 
      for (int i=0; i < nList.getLength(); i++) { 
       node = nList.item(i); 
       if (node.getNodeType() == Node.ELEMENT_NODE) { 
        element2 = (Element) node; 
        list.add((getValue("name", element2)+"\n")); 
        list2.add((getValue("salary", element2)+"\n")); 
       } 
      } 
     } catch (Exception e) { 
      e.printStackTrace(); 
     } 
     setListAdapter (new ArrayAdapter<String>(
          second.this, android.R.layout.simple_list_item_1,list));     
    } 

    private static String getValue(String tag, Element element) { 
     NodeList nodeList = element.getElementsByTagName(tag).item(0).getChildNodes(); 
     Node node = (Node) nodeList.item(0); 
     return node.getNodeValue(); 
    }

來源

2013-10-03 SreBalaji Thirumalai

是否使用資產中的文件？ – Yashasvi

也，發佈你的xml！ – Yashasvi

其實這是列表視圖類型...所以我沒有做任何事情的XML文件.... –

試試這個..嘗試抓到底，確保從XML DOM解析你獲得的所有值或不..我希望這將有助於..

LinearLayout linearLayout = new LinearLayout(this); 
    ListView listView = new ListView(this); 
    ArrayAdapter<String> aR = new ArrayAdapter<String>(second.this, android.R.layout.simple_list_item_1,list); 
    listView.setAdapter(aR); 
    linearLayout.addView(listView); 
    setContentView(linearLayout);

來源

2013-10-04 16:07:26 Hariharan

我在下面的代碼中解析xml在dom中的空白屏幕android

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