問題，在存儲過程中

用戶定義的表類型我創建了一個用戶derfined表類型如下問題，在存儲過程中

CREATE TYPE [emp_TT] AS TABLE 
(
em_number   char(12), 
email    varchar(50), 
emergency_relation char(32), 
option1    char(16), 
) 
GO

它得到的類型下，創建爲

，並試圖在使用它們我的存儲過程像

ALTER PROCEDURE [dbo].[uspInsertorUpdateArchibusINF] 
@emp_TT AS emp_TT READONLY 
AS 
BEGIN 
SET NOCOUNT ON; 

BEGIN TRANSACTION; 

UPDATE e 
SET e.email     = t.email, 
    e.emergency_relation = t.emergency_relation, 
    e.option1    = t.option1, 
    FROM [afm].[em] e 
    INNER JOIN @emp_TT t ON e.em_id = t.em_id 

    INSERT INTO [afm].[em](email, emergency_relation, option1, em_id) 
    SELECT t.email 
    , t.emergency_relation,t.option1 
    , t.em_id 
FROM @emp_TT t 
WHERE NOT EXISTS (SELECT 1 
       FROM [afm].[em] 
       WHERE em_id = t.em_id) 
COMMIT TRANSACTION; 

END;

當我執行存儲過程重則引發錯誤像

Column, parameter, or variable #1: Cannot find data type emp_TT. Parameter or variable '@emp_TT' has an invalid data type.

Must declare the table variable "@emp_TT".

請讓我知道我在這裏失蹤

來源

2017-05-23 Sid

我不知道你會做什麼......只是先刪除它。從emp_TT AS emp_TT READONLY到emp_TT emp_TT READONLY在emp_TT變量處使用@ sign。 –

使用模式afm像afm.emp_TT在第2行的如下所示

ALTER PROCEDURE [dbo].[uspInsertorUpdateArchibusINF] 
@emp_TT AS afm.emp_TT READONLY 
AS 
BEGIN 
SET NOCOUNT ON; 

BEGIN TRANSACTION; 

UPDATE e 
SET e.email     = t.email, 
    e.emergency_relation = t.emergency_relation, 
    e.option1    = t.option1, 
    FROM [afm].[em] e 
    INNER JOIN @emp_TT t ON e.em_id = t.em_id 

    INSERT INTO [afm].[em](email, emergency_relation, option1, em_id) 
    SELECT t.email 
    , t.emergency_relation,t.option1 
    , t.em_id 
FROM @emp_TT t 
WHERE NOT EXISTS (SELECT 1 
       FROM [afm].[em] 
       WHERE em_id = t.em_id) 
COMMIT TRANSACTION; 

END;

來源

2017-05-23 14:28:32

你需要聲明它下面..like，用它

DECLARE @emp_TT AS emp_TT 

INSERT INTO @emp_TT 
ALL VALUES

如今終於之前，你可以傳遞到存儲過程

exec [dbo].[uspInsertorUpdateArchibusINF] @emp_tt

來源

2017-05-23 14:32:36 TheGameiswar

CREATE TYPE [emp_TT] AS TABLE 
(
em_number   char(12), 
email    varchar(50), 
emergency_relation char(32), 
option1    char(16) --Removed , here 
) 
GO 


ALTER PROCEDURE [dbo].[uspInsertorUpdateArchibusINF] 
@emp_TT AS emp_TT READONLY 
AS 
BEGIN 
SET NOCOUNT ON; 

BEGIN TRANSACTION; 

UPDATE e 
SET e.email     = t.email, 
    e.emergency_relation = t.emergency_relation, 
    e.option1    = t.option1 --Removed , here 
    FROM [afm].[em] e 
    INNER JOIN @emp_TT t ON e.em_id = t.em_id 

    INSERT INTO [afm].[em](email, emergency_relation, option1, em_id) 
    SELECT t.email 
    , t.emergency_relation,t.option1 
    , t.em_id 
FROM @emp_TT t 
WHERE NOT EXISTS (SELECT 1 
       FROM [afm].[em] 
       WHERE em_id = t.em_id) 
COMMIT TRANSACTION; 

END;

像執行存儲過程低於

DECLARE @emp_TT AS [emp_TT] 

INSERT INTO @emp_TT 
SELECT 'Your All Values' 

EXEC [dbo].[uspInsertorUpdateArchibusINF] @emp_tt

來源

2017-05-23 14:36:18

問題，在存儲過程中

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