2
我有2個表:記錄排序爲:n(一對多)關係
+-----------+ +------------------------------------+--------------+
+ persons | | photos |
+-----------| +---------------------------------------------------+
+ id | name + | id | person_id | path | title |
+-----------+ +---------------------------------------------------+
+ 1 | Tom + | 1 | 2 | ~fred/me.png | Yo, it's Me! |
+ 2 | Fred + | 2 | 2 | ~fred/my_wife.png | I'm Susan |
+ 3 | Jack + | 3 | 1 | ~tom/my_dog.jpg | a woof |
+-----------+ +---------------------------------------------------+
具有在這種關係:
人的hasMany照片< - >照片屬於人
我想列出所有人與他們的照片(即使有人沒有一個,如傑克)和照片的順序命名。
我應該爲此編寫什麼SQL查詢(MySQL)?我可以在一對多關係中使用連接嗎?
PS:只是作爲一個信息,我希望能夠建立這樣一個陣列中的記錄:
$persons = Array(
[0] => Array(
[id] => 1,
[name] => 'Tom',
[Photo] => Array(
[0] => Array(
[id] => 3,
[person_id] => 1,
[path] => '~tom/my_dog.jpg',
[title] => 'a woof' // 1st
)
)
),
[1] => Array(
[id] => 2,
[name] => 'Fred',
[Photo] => Array(
[0] => Array(
[id] => 2,
[person_id] => 2,
[path] => '~fred/my_wife.png',
[title] => "I'm Susan" // 2nd
),
[0] => Array(
[id] => 1,
[person_id] => 2,
[path] => '~fred/me.png',
[title] => "Yo, it's Me!" // 3rd
)
)
),
[2] => Array(
[id] => 3,
[name] => 'Jack',
[Photo] => Array()
)
)
非常感謝!
+1擊敗了我,抹去了我自己的帖子:) – 2009-08-09 19:50:29