排除節假日2個日期

Question

我已經找遍了互聯網之間，我終於這段代碼在 Weekend Exclusion。

OR

function calcBusinessDays(dDate1, dDate2) { // input given as Date objects 
    var iWeeks, iDateDiff, iAdjust = 0; 
    if (dDate2 < dDate1) return -1; // error code if dates transposed 
    var iWeekday1 = dDate1.getDay(); // day of week 
    var iWeekday2 = dDate2.getDay(); 
    iWeekday1 = (iWeekday1 == 0) ? 7 : iWeekday1; // change Sunday from 0 to 7 
    iWeekday2 = (iWeekday2 == 0) ? 7 : iWeekday2; 
    if ((iWeekday1 > 5) && (iWeekday2 > 5)) iAdjust = 1; // adjustment if both days on weekend 
    iWeekday1 = (iWeekday1 > 5) ? 5 : iWeekday1; // only count weekdays 
    iWeekday2 = (iWeekday2 > 5) ? 5 : iWeekday2; 

    // calculate differnece in weeks (1000mS * 60sec * 60min * 24hrs * 7 days = 604800000) 
    iWeeks = Math.floor((dDate2.getTime() - dDate1.getTime())/604800000) 

    if (iWeekday1 <= iWeekday2) { 
     iDateDiff = (iWeeks * 5) + (iWeekday2 - iWeekday1) 
    } else { 
     iDateDiff = ((iWeeks + 1) * 5) - (iWeekday1 - iWeekday2) 
    } 

    iDateDiff -= iAdjust // take into account both days on weekend 

    return (iDateDiff + 1); // add 1 because dates are inclusive 
    } 

我不知道如何添加代碼，以排除假期。我知道我必須創建一個數組來存儲假期，但之後我堅持了一點。我需要你的幫助，非常感謝。

Answer 1

通過假期陣列只是循環和檢查日期落在範圍內，也檢查節日是在這種情況下，它已經算週六或週日。下面是修改的例子。

function calcBusinessDays(dDate1, dDate2, holidays) { // input given as Date objects 
    var iWeeks, iDateDiff, iAdjust = 0, i; 
    if (dDate2 < dDate1) return -1; // error code if dates transposed 
    var iWeekday1 = dDate1.getDay(); // day of week 
    var iWeekday2 = dDate2.getDay(); 
    iWeekday1 = (iWeekday1 == 0) ? 7 : iWeekday1; // change Sunday from 0 to 7 
    iWeekday2 = (iWeekday2 == 0) ? 7 : iWeekday2; 
    if ((iWeekday1 > 5) && (iWeekday2 > 5)) iAdjust = 1; // adjustment if both days on weekend 
    iWeekday1 = (iWeekday1 > 5) ? 5 : iWeekday1; // only count weekdays 
    iWeekday2 = (iWeekday2 > 5) ? 5 : iWeekday2; 

    // calculate differnece in weeks (1000mS * 60sec * 60min * 24hrs * 7 days = 604800000) 
    iWeeks = Math.floor((dDate2.getTime() - dDate1.getTime())/604800000) 

    if (iWeekday1 <= iWeekday2) { 
     iDateDiff = (iWeeks * 5) + (iWeekday2 - iWeekday1) 
    } else { 
     iDateDiff = ((iWeeks + 1) * 5) - (iWeekday1 - iWeekday2) 
    } 

    iDateDiff -= iAdjust; // take into account both days on weekend 

    for(i = 0; i < holidays.length; i++) { 
     if(holidays[i] >= dDate1 && holidays[i] <= dDate2 && holidays[i].getDay() != 0 && holidays[i].getDay() != 6) { 
     iDateDiff--; 
     } 
    } 

    return (iDateDiff + 1); // add 1 because dates are inclusive 
    } 

var holidays = [ new Date(2017, 5, 2), new Date(2017, 5, 3), new Date(2017, 5, 4), new Date(2017, 5, 5) ]; 

calcBusinessDays(new Date(2017,1,1), new Date(), holidays); 
// returns 93