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準備sql查詢問題。使用分區計算所有狀態和特定狀態的數量
CREATE TABLE right_data(RID NUMBER(9,0), STATUS NUMBER(2,0));
CREATE TABLE left_data(LID NUMBER(9,0), URL VARCHAR(70 BYTE));
CREATE TABLE left_to_right(LID NUMBER(9,0), RID NUMBER(9,0));
INSERT INTO right_data (RID, STATUS) VALUES (1,0);
INSERT INTO right_data (RID, STATUS) VALUES (2,1);
INSERT INTO right_data (RID, STATUS) VALUES (3,0);
INSERT INTO right_data (RID, STATUS) VALUES (4,0);
INSERT INTO right_data (RID, STATUS) VALUES (5,1);
INSERT INTO left_data (LID, URL) VALUES (1,'data_1');
INSERT INTO left_data (LID, URL) VALUES (2,'data_2');
INSERT INTO left_data (LID, URL) VALUES (3,'data_3');
INSERT INTO left_data (LID, URL) VALUES (4,'data_4');
INSERT INTO left_data (LID, URL) VALUES (5,'data_5');
INSERT INTO left_to_right (LID, RID) VALUES (1,1);
INSERT INTO left_to_right (LID, RID) VALUES (1,2);
INSERT INTO left_to_right (LID, RID) VALUES (2,1);
INSERT INTO left_to_right (LID, RID) VALUES (1,4);
INSERT INTO left_to_right (LID, RID) VALUES (4,3);
INSERT INTO left_to_right (LID, RID) VALUES (5,1);
INSERT INTO left_to_right (LID, RID) VALUES (3,5);
INSERT INTO left_to_right (LID, RID) VALUES (4,2);
錯誤的查詢。
SELECT
DISTINCT left_to_right.LID
, COUNT(left_to_right.RID) OVER (PARTITION BY left_to_right.LID) AS NUM_RID
, COUNT(left_to_right.RID) OVER (PARTITION BY
left_to_right.LID
AND
right_data.STATUS = 1
) AS NUM_RID_S1
FROM
left_to_right
JOIN
right_data
ON
right_data.RID = left_to_right.RID
ORDER BY left_to_right.LID;
我怎麼能在同一查詢LID /(數均right_data.status)和LID數/(right_data.status數爲1)?
這並不壞。只是不在所有的數據中我需要什麼。 – 2013-02-26 16:45:07
@IstvánSimon。 。 。我知道。我提出了更好的答案。 – 2013-02-26 16:46:46