閃電++數組結構

Question

我想有一個結構中有幾個閃電++數組。這個程序創建了這樣一個結構，但我無法正確分配對象。是唯一的替代方案，將指針的結構制定爲在結構外部分配的blitz ++數組？

#include <iostream> 
#include <blitz/array.h> 

using namespace std; 
using namespace blitz; 

struct Bstruct{ 
    Array<double,1> B; 
}; 

int main(){ 

    Bstruct str; 
    Array<double,1> x(10); 
    x = 1.0; 
    str.B = x; 

    cout << "x = " << x << endl; 
    cout << "str.B = " << str.B << endl; 

    return 0; 
} 

➜ blitz_struct git:(master) ✗ ./struct 
x = (0,9) 
[ 1 1 1 1 1 1 1 1 1 1 ] 

str.B = (0,-1) 
[ ] 

Answer 1

，我發現這個工作：

#include <iostream> 
#include <blitz/array.h> 

using namespace std; 
using namespace blitz; 

struct Bstruct{ 
    Array<double,1> B; 
}; 

int main(){ 

    Bstruct str; 
    Array<double,1> x(10); 
    x = 1.0; 
    str.B.resize(10); 
    str.B = 1.0; 

    cout << "x = " << x << endl; 
    cout << "str.B = " << str.B << endl; 

    return 0; 
} 

➜ blitz_struct git:(master) ✗ ./struct      
x = (0,9) 
[ 1 1 1 1 1 1 1 1 1 1 ] 

str.B = (0,9) 
[ 1 1 1 1 1 1 1 1 1 1 ]