SQL服務器記錄鏈接字符串匹配後

Question

背景 - 我有一組客戶數據和使用的字符串匹配算法來比較的所有記錄的相似性。然後，我需要直接或通過關聯將彼此相關的結果進行分組，併爲每個組應用唯一的ID。

問題 - 我不能想辦法以連接在一起的記錄，並應用一個唯一的ID爲每個組

例

數據目前看起來是這樣的，已找到的匹配（MatchScore與此處的問題無關，只是爲了證明數據來自哪裏）。

+-------------+-------------+------------+ 
| CustomerID1 | CustomerID2 | MatchScore | 
+-------------+-------------+------------+ 
|  2021000 |  2707799 | 0.075  | 
|  2021000 |  3856308 | 0.082  | 
|  774062 |  774063 | 0.041  | 
|  998328 |  2278386 | 0.063  | 
|  998328 |  998329 | 0.058  | 
|  998329 |  2278386 | 0.030  | 
+-------------+-------------+------------+ 

底部的3條記錄都是鏈接的，因此我希望它們有相同的ID關聯。

visual image of these records all being related

這就是我想要的數據看起來像

+----+-------------+-------------+------------+ 
| ID | CustomerID1 | CustomerID2 | MatchScore | 
+----+-------------+-------------+------------+ 
| 1 |  998328 |  2278386 | 0.063  | 
| 1 |  998328 |  998329 | 0.058  | 
| 1 |  998329 |  2278386 | 0.030  | 
| 2 |  2021000 |  2707799 | 0.075  | 
| 2 |  2021000 |  3856308 | 0.082  | 
| 3 |  774062 |  774063 | 0.041  | 
+----+-------------+-------------+------------+ 

或類似

+----+------------+ 
| ID | CustomerID | 
+----+------------+ 
| 1 | 2278386 | 
| 1 |  998328 | 
| 1 |  998329 | 
| 2 | 2021000 | 
| 2 | 2707799 | 
| 2 | 3856308 | 
| 3 |  774062 | 
| 3 |  774063 | 
+----+------------+ 

代碼來生成示例表

select '998328' as CustomerID1,'998329' as CustomerID2,'0.058' as MatchScore 
into #tmp 
union 
select '998328' as CustomerID1,'2278386' as CustomerID2,'0.063' as MatchScore 
union 
select '998329' as CustomerID1,'2278386' as CustomerID2,'0.030' as MatchScore 
union 
select '2021000' as CustomerID1,'2707799' as CustomerID2,'0.075' as MatchScore 
union 
select '2021000' as CustomerID1,'3856308' as CustomerID2,'0.082' as MatchScore 
union 
select '774062' as CustomerID1,'774063' as CustomerID2,'0.041' as MatchScore 

select * from #tmp 

正如我所說，我不知道如何將記錄聯繫在一起，我嘗試了各種聯合，但是尤里卡時刻從未到來。請你幫忙。

感謝

Answer 1

我不知道這是你期望的結果，

with tmp as(
select '998328' as CustomerID1,'998329' as CustomerID2,'0.058' as MatchScore 
union 
select '998328' as CustomerID1,'2278386' as CustomerID2,'0.063' as MatchScore 
union 
select '998329' as CustomerID1,'2278386' as CustomerID2,'0.030' as MatchScore 
union 
select '2021000' as CustomerID1,'2707799' as CustomerID2,'0.075' as MatchScore 
union 
select '2021000' as CustomerID1,'3856308' as CustomerID2,'0.082' as MatchScore 
union 
select '774062' as CustomerID1,'774063' as CustomerID2,'0.041' as MatchScore 
union 
select '774063' as CustomerID1,'774062' as CustomerID2,'0.041' as MatchScore 
union 
select '774063' as CustomerID1,'774063' as CustomerID2,'0.041' as MatchScore) 


select DENSE_RANK() OVER(ORDER BY rank_value) id, t1.CustomerID1, t1.CustomerID2 
from(
    select 
     t1.*, 
     case 
      when t2.CustomerID1 IS NOT NULL 
       THEN t2.CustomerID1 
      ELSE t3.CustomerID1 
     end rank_value 

    from tmp t1 
    left join tmp t2 
    on (t1.CustomerID1 = t2.CustomerID2 
      and t1.CustomerID2!=t2.CustomerID1 
      and (t1.CustomerID1 != t1.CustomerID2 and t2.CustomerID1 != t2.CustomerID2)) 
     or (t1.CustomerID1 = t2.CustomerID1 
      and t1.CustomerID2 != t2.CustomerID2 
      and (t1.CustomerID1 != t1.CustomerID2)) 
    left join tmp t3 
     on t1.CustomerID1 = t3.CustomerID2 
      and t1.CustomerID2=t3.CustomerID1 
)t1 

我得到下面的結果

注：DENSE_RANK()功能可用從版本2012