iOS的時間順序來的NSString的

Question

一個NSArray我需要一個NSArray包含時間NSString的，如排序，

NSMutableArray *times = [[NSMutableArray alloc]initWithObjects:@"09:00 AM",@"07:30 AM",@"06:45 PM",@"05:00 PM",@"12:45 AM",@"12:45 PM",@"01:00 AM",@"01:15 PM", nil]; 

我需要做的是在時間的升序排序的數組。
有沒有辦法做這樣的事情？

Answer 1

NSMutableArray *times = [[NSMutableArray alloc]initWithObjects:@"09:00 AM",@"07:30 AM",@"06:45 PM",@"05:00 PM",@"12:45 AM",@"12:45 PM",@"01:00 AM",@"01:15 PM", nil]; 

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setDateFormat:@"hh:mm a"]; 

NSArray *sortedTimes = [times sortedArrayUsingComparator:^NSComparisonResult(NSString *obj1, NSString *obj2) 
{ 
    NSDate *date1 = [dateFormatter dateFromString:obj1]; 
    NSDate *date2 = [dateFormatter dateFromString:obj2]; 
    return [date1 compare:date2]; 
}]; 

優化版本：

NSMutableArray *times = [[NSMutableArray alloc]initWithObjects:@"09:00 AM",@"07:30 AM",@"06:45 PM",@"05:00 PM",@"12:45 AM",@"12:45 PM",@"01:00 AM",@"01:15 PM", nil]; 

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setDateFormat:@"hh:mm a"]; 

NSMutableArray *dates = [NSMutableArray arrayWithCapacity:times.count]; 
for (NSString *timeString in times) 
{ 
    NSDate *date = [dateFormatter dateFromString:timeString]; 
    [dates addObject:date]; 
} 

[dates sortUsingSelector:@selector(compare:)]; 

NSMutableArray *sortedTimes = [NSMutableArray arrayWithCapacity:dates.count]; 
for (NSDate *date in dates) 
{ 
    NSString *timeString = [dateFormatter stringFromDate:date]; 
    [sortedTimes addObject:timeString]; 
} 

Answer 2

由於這些字符串將sored爲

01:15，12:25，05:00 ....

而且他們也不NSDate。

所以你需要做的是，從這些字符串創建一個具有NSDate的並行數組，對數組進行排序並提取這些值。

---

儘管實現我解決了它的新手方式

NSMutableArray *times = [[NSMutableArray alloc]initWithObjects:@"09:00 AM",@"07:30 AM",@"06:45 PM",@"05:00 PM",@"12:45 AM",@"12:45 PM",@"01:00 AM",@"01:15 PM", nil]; 

NSMutableArray *dates=[NSMutableArray new]; 

NSDateFormatter *dateFormatter=[NSDateFormatter new]; 
[dateFormatter setDateFormat:@"hh:mm a"]; 

for (NSString *stringDate in times) { 
     NSDate *date=[dateFormatter dateFromString:stringDate]; 
     [dates addObject:date]; 
} 

NSSortDescriptor *descriptor = [[NSSortDescriptor alloc] initWithKey:@"self" ascending:YES]; 
NSArray *descriptors = [NSArray arrayWithObject: descriptor]; 
NSArray *reverseOrder = [dates sortedArrayUsingDescriptors:descriptors]; 

[times removeAllObjects]; 
for (NSDate *date in reverseOrder) { 
     NSString *string=[dateFormatter stringFromDate:date]; 
     [times addObject:string]; 
} 

NSLog(@"%@",times); 

Answer 3

對於NSDate的比較使用：

+ (BOOL)isDate:(NSDate *)date1 smallerThanAnotherDate:(NSDate *)date2 
{ 
    NSDate* enddate = date1; 
    NSDate* currentdate = date2; 
    NSTimeInterval distanceBetweenDates = [enddate timeIntervalSinceDate:currentdate]; 
    double secondsInMinute = 60; 
    NSInteger secondsBetweenDates = distanceBetweenDates/secondsInMinute; 

    if (secondsBetweenDates == 0) 
     return YES; 
    else if (secondsBetweenDates < 0) 
     return YES; 
    else 
     return NO; 
} 

所以，如果你不想轉換您小時的NSDate做到這一點單獨適用於我

NSArray *sortedTimes = [times sortedArrayUsingSelector:@selector(localizedStandardCompare:)]; 

Answer 4

你可以試試這個代碼：

NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; 
    [formatter setDateFormat:@"hh:mm a"]; 
    [times sortUsingComparator:^NSComparisonResult(NSString* obj1, NSString *obj2) { 
     NSDate *firstDate = [formatter dateFromString:obj1]; 
     NSDate *secondDate = [formatter dateFromString:obj2]; 
     return [firstDate compare:secondDate]; 
    }];