從模型中使用功能

Question

Users.php（模型）：

... 
public function hashPassword($password){ 
    $hashed = hash('sha256', $password . self::HASH_CODE); 
    return $hashed; 
} 
... 

UserIdentity.php

... 
else if($user->password!==Users::hashPassword($this->password)) 
... 

錯誤：

Non-static method Users::hashPassword() should not be called statically, assuming $this from incompatible context 

Answer 1

你需要定義hashPassword()爲靜態功能以便用Users::hashPassword()調用它：

public static function hashPassword($password) { 
    ... 

否則，您可以創建Users類的實例，並調用它在一個非靜態的方式：

$users = new Users(); 
$users->hashPassword($password); 

在strictly- yii感，你可以用下面的調用它（根據您的設置）：

Yii::app()->Users->hashPassword($password); 

Answer 2

else if($user->password!==Users::model()->hashPassword($this->password)) 

這不是一個靜態方法

Answer 3

製作功能static

public static function hashPassword($password){ 
    $hashed = hash('sha256', $password . self::HASH_CODE); 
    return $hashed; }