2012-09-01 58 views
1

我正在構建一個3d(紅色,青色)程序。它進行得很好,但是當結合時,「圖像」(見代碼)似乎沒有受到影響。鎖定位不會影響我的圖像

我的錯誤是什麼?

假設:

RImage_P(point) = {5,5} 
startCyan(point) = {0,0} 
startRed(point) = {5,5} 

CImageRImage是下面的代碼。 圖像結果是一個完全黑色的透明圖像。 爲了測試和調試,我評論了Alpha(結果相同)。

private void bitCombine(System.Drawing.Point startCyan, System.Drawing.Point startRed) 
{ 
    using (Bitmap image = new Bitmap(CImage.Width + Math.Abs(RImage_P.X), CImage.Height + Math.Abs(RImage_P.Y),PixelFormat.Format32bppArgb)) 
    { 
     var rectfull = new Rectangle(0, 0, image.Width, image.Height); 
     var rect = new Rectangle(0, 0, CImage.Width, CImage.Height); 
     var bitsC = CImage.LockBits(rect, ImageLockMode.ReadOnly 
            , PixelFormat.Format32bppArgb); 
     var bitsA = alpha.LockBits(rect, ImageLockMode.ReadOnly 
            , PixelFormat.Format32bppArgb); 
     var bitsOutput = image.LockBits(rectfull, ImageLockMode.WriteOnly 
            , PixelFormat.Format32bppArgb); 
     unsafe 
     { 
      for (int y = 0; y < CImage.Height; y++) 
      { 
       byte* ptrC = (byte*)bitsC.Scan0 + y * bitsC.Stride; 
       byte* ptrA = (byte*)bitsA.Scan0 + y * bitsA.Stride; 
       byte* ptrOutput = (byte*)bitsOutput.Scan0 
            + (y+startCyan.Y)* bitsOutput.Stride; 
       for (int x = 0; x < CImage.Width; x++)// cyan values 
       {// gui+ is reversed BGRA 
        ptrOutput[4 * (x+startCyan.X)] = ptrC[4 * x];   // blue 
        ptrOutput[4 * (x + startCyan.X) + 1] = ptrC[4 * x + 1];// green 
        //ptrOutput[4 * (x + startCyan.X) + 3] = ptrA[4 * x + 3];// alpha 
       } 
      } 
      CImage.UnlockBits(bitsC); 

      var bitsR = RImage.LockBits(rect, ImageLockMode.ReadOnly 
             , PixelFormat.Format32bppArgb); 
      for (int y = 0; y < RImage.Height; y++)// red values 
      { 
       byte* ptrR = (byte*)bitsR.Scan0 + y * bitsR.Stride; 
       byte* ptrA = (byte*)bitsA.Scan0 + y * bitsA.Stride; 
       byte* ptrOutput = (byte*)bitsOutput.Scan0 
            + (y+ startRed.Y) * bitsOutput.Stride; 
       for (int x = 0; x < RImage.Width; x++) 
       {// gui+ is reversed BGRA 
        ptrOutput[4 * (x + startRed.X) + 2] = ptrR[4 * x + 2]; // red 
        //ptrOutput[4 * (x + startRed.X) + 3] = ptrA[4 * x + 3];// alpha 
       } 
      } 

      RImage.UnlockBits(bitsR); 
      alpha.UnlockBits(bitsA); 
      image.UnlockBits(bitsOutput); 


      this.image = image; 
     } 
    } 
} 

這些圖像:

CIamge RImage

+1

發佈的代碼將永遠不會設置藍色和alpha,alpha在0將產生黑色圖像。通過從非常小的位圖開始調試代碼,以便更好地跟蹤輸入和輸出。 –

回答

0

我發現與它不工作的圖像可視化,但α通道是= O 答案是改變alpha通道的值到255.

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