PDO更新幫助執行PDO更新

的變量：$表的更新是發生表和$字段在表中的字段，和$生成的值從後並投入$值陣列和$哪裏是表的索引字段的id的值，$ indxfldnm是索引字段名稱

function SQLUpdate($table,$fields,$values,$where,$indxfldnm) { 

    //Connect to DB 
    $dbaddr = DB_HOST; 
    $dbusr = DB_USER; 
    $dbpwd = DB_PASSWORD; 
    $dbname = DB_DATABASE; 

    $db = new PDO('mysql:host='.$dbaddr .';dbname='.$dbname.';charset=UTF8', $dbusr, $dbpwd); 

    //build the fields 
    $buildFields = ''; 
    if (is_array($fields)) { 

    //loop through all the fields 
    foreach($fields as $key => $field) : 
     if ($key == 0) { 
     //first item 
     $buildFields .= $field; 
     } else { 
     //every other item follows with a "," 
     $buildFields .= ', '.$field; 
     } 
    endforeach; 

    } else { 
    //we are only inserting one field 
    $buildFields .= $fields; 
    } 

    //build the values 
    $buildValues = ''; 
    if (is_array($values)) { 

    //loop through all the values 
    foreach($values as $key => $value) : 
     if ($key == 0) { 
     //first item 
     $buildValues .= '?'; 
     } else { 
     //every other item follows with a "," 
     $buildValues .= ', ?'; 
     } 
    endforeach; 

    } else { 
    //we are only updating one field 
    $buildValues .= ':value'; 
    } 
$sqlqry = 'UPDATE '.$table.' SET ('.$buildFields.' = '.$buildValues.') WHERE `'.$indxfldnm.'` = \''.$where.'\');'; 

    $prepareUpdate = $db->prepare($sqlqry); 
    //execute the update for one or many values 
    if (is_array($values)) { 
    $prepareUpdate->execute($values); 
    } else { 
    $prepareUpdate->execute(array(':value' => $values)); 
    } 

    //record and print any DB error that may be given 
    $error = $prepareUpdate->errorInfo(); 
    if ($error[1]) print_r($error); 



echo $sqlqry; 
return $sqlqry; 
}

到目前爲止好但是其不工作將值傳遞到正確的更新語句中的字段時出現錯誤，但我對pdo不太熟悉並將其設置爲有點幫助，可以修復代碼以將參數綁定到更新中的值不勝感激

謝謝

來源

2014-12-07 Danny F

嘗試讓這個在你的函數

<?php 
$servername = "localhost"; 
$username = "username"; 
$password = "password"; 
$dbname = "myDBPDO"; 

try { 
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); 
    // set the PDO error mode to exception 
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

    $sql = "UPDATE MyGuests SET lastname='Doe' WHERE id=2"; 

    // Prepare statement 
    $stmt = $conn->prepare($sql); 

    // execute the query 
    $stmt->execute(); 

    // echo a message to say the UPDATE succeeded 
    echo $stmt->rowCount() . " records UPDATED successfully"; 
    } 
catch(PDOException $e) 
    { 
    echo $sql . "<br>" . $e->getMessage(); 
    } 

$conn = null; 
?>

來源

2014-12-07 11:10:54 Apurva

我有多個值，它的構建，我需要的字段和值轉換成可以重現「更新」 sqlquery的辦法多個字段。這是問題。我如何構建SQL？把它發送到準備課程？ – 2014-12-07 15:25:14

改變的代碼到一個不同的構建：

這消除了多值問題

function SQLUpdate($table,$fields,$values,$where,$indxfldnm) { 


    $dbdata = array(); 
    $i=0; 

    foreach ($fields as $fld_nm) 
    { 
     if ($i > 0) { 
     $dbdata[$fld_nm] = $values[$i]; } 
     $i++; 

    } //end foreach 
$buildData = ''; 
foreach ($dbdata as $key => $val) { 
    if (empty($val)) {$buildData .= '`'.$key.'` = \'NULL\', ';} else { 
    $buildData .= '`'.$key.'` = \''.$val.'\', ';} 

} 
$buildData = substr($buildData,0,-2); 


    $dbaddr = DB_HOST; 
    $dbusr = DB_USER; 
    $dbpwd = DB_PASSWORD; 
    $dbname = DB_DATABASE; 
$prepareUpdate =''; 
try { 
    $db = new PDO('mysql:host='.$dbaddr .';dbname='.$dbname.';charset=UTF8', $dbusr, $dbpwd); 
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
$db->exec("SET CHARACTER SET utf8"); 

$sqlqry = 'UPDATE '.$table.' SET '.$buildData.' WHERE `'.$indxfldnm.'` = \''.$where.'\';'; 

    $prepareUpdate = $db->exec($sqlqry); 
    //execute the update for one or many values 
} 
catch(PDOException $e) 
    { 
    $e->getMessage(); 
    print_r($e); 
    } 


return $sqlqry; 


} 
//END: SQLUpdate

來源

2014-12-07 16:15:21

PDO更新幫助執行PDO更新

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