使用Xpath的經緯度報廢

Question

我正在嘗試進行Web數據挖掘。我正在使用Xpath嘗試從瀏覽器上的地圖上刮取圖像和經緯度。圖像位於嵌套表格中，這一系列圖像的路徑給我一個問題。經緯度也在腳本中，我需要提取任何人都知道如何去做這件事。

這裏是由螢火蟲所示，顯示geopoints功能我對圖像

<?php 
    $baseUrl='http://www.hassconsult.co.ke/'; 
    $dom = new DOMDocument(); 
    @$dom->loadHTMLFile('http://www.hassconsult.co.ke/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&google=1'); 
    $xpath = new DOMXPath($dom); 

    foreach($xpath->query("//div[@id='mainbody']/table") as $table) { 
    echo $xpath->query(".//img", $table)->item(0)->getAttribute('src'). "\n"; 
    echo $xpath->query(".//tr[3]/td/a/img", $table)->item(0)->getAttribute('src'). "\n";; 
    } 

    ?> 

here is the table outline as shown using firebug for the images 

    <div id="mainbody"> 
<table width="502" cellspacing="0" cellpadding="0" border="0"> 
<tbody> 
<tr> 
<tr> 
<tr> 
<td valign="top" height="69"> 
<a href="/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&photo_no=1"> 
<img width="50" height="45" border="0" style="border:1px #993300 solid;" alt="logo" src="/images/photos/p569_1.jpg"> 
</a> 
<a href="/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&photo_no=2"> 
<img width="50" height="45" border="0" style="border:1px #993300 solid;" alt="logo" src="/images/photos/p569_2.jpg"> 
</a> 
<a href="/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&photo_no=3"> 
<img width="50" height="45" border="0" style="border:1px #993300 solid;" alt="logo" src="/images/photos/p569_3.jpg"> 
</a> 
<a href="/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&photo_no=4"> 
<img width="50" height="45" border="0" style="border:1px #993300 solid;" alt="logo" src="/images/photos/p569_4.jpg"> 
</a> 
<a href="/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&photo_no=5"> 
<img width="50" height="45" border="0" style="border:1px #993300 solid;" alt="logo" src="/images/photos/p569_5.jpg"> 
</a> 
<a href="/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&photo_no=6"> 
<img width="50" height="45" border="0" style="border:1px #993300 solid;" alt="logo" src="/images/photos/p569_6.jpg"> 
</a> 
<a href="/index.php?option=com_content&view=article&id=27&Itemid=74&send=5&ref_no=834/II&photo_no=7"> 
<img width="50" height="45" border="0" style="border:1px #993300 solid;" alt="logo" src="/images/photos/p569_7.jpg"> 
</a> 
<div style="font-family:Arial, Helvetica, sans-serif;font-size:12px;font-weight:bold;color:#FF9900;padding-top:10px;"></div> 
<strong> 
<br> 
<div style="font-family:Arial, Helvetica, sans-serif;font-size:12px;color:#000000;text-align:justify;"> 
</td> 
</tr> 
<tr> 
<tr> 
</tbody> 
</table> 
</div> 
</div> 

這裏代碼

<tr> 
<td> 
<br> 
<br> 
<div id="map_canvas" style="width: 450px; height: 450px; position: relative; background-color: rgb(229, 227, 223);"> 
<script> 
function initialize() { 
if (GBrowserIsCompatible()) { 
var map = new GMap2(document.getElementById("map_canvas")); 
var point = new GLatLng(-1.242831, 36.777805);//how will i pick these values and echo 
map.setCenter(point, 16); 
map.addControl(new GLargeMapControl()); 
map.addControl(new GMapTypeControl()); 
map.addControl(new GScaleControl()); 
map.setUIToDefault(); 
map.setMapType(G_NORMAL_MAP); 
var marker = new GMarker(point); 
map.addOverlay(marker); 
GEvent.addListener(marker, "click", function() {marker.openInfoWindowHtml('<h3>Hillview<br /><a href="http://maps.google.com/maps?saddr=&daddr=' + point.toUrlValue() + '" target ="_blank">Get Directions<\/a>');}); 
} 
} 
window.onload = initialize; 
window.onunload = GUnload; 
</script> 
</td> 
</tr> 

Answer 1

您可以使用XPath拿到劇本的內容，但你需要（理想的JS解析器）或正則表達式來獲得這些值：

$src = $xpath->query("//script")->item(0)->nodeValue; 
preg_match('/GLatLng\(([\d.-]+), ([\d.-]+)\)/', $src, $m); 
list(, $lat, $lng) = $m;