我得到所有來自mysql數據庫的HTML表格行中的關鍵字。所以當我點擊每個關鍵字時,它調用keywordBox
id使用jQuery將kid
添加到使用php的mysql數據庫。我用while循環來獲得所有kid
,但我只得到一個kid
。爲什麼?這是應該得到不同kid
當我在不同的keyword
無法獲得所有的ID在php哪個循環使用jquery
以下點擊是我的代碼:
echo "<div id='keywordBox'>";
echo '<table border="0" cellpadding="0" cellspacing="0" width="1055">';
$count = 0;
while($result = mysql_fetch_array($query)){
if($count%6==0 && $count!=0)
echo '</tr><tr>';
elseif($count==0) echo '<tr>';
$kid = $result['kid'];
$keywordName = ucfirst($result['keywordName']);
$keyword_short_name = ucfirst($result['keyword_short_name']);
$keyword_full_name = ucfirst($result['keyword_full_name']);
echo "<input type='hidden' id='kid' value='$kid'/>";
echo "<input type='hidden' id='cdid' value='$cdid'/>";
echo "<td width='400'><strong>$keyword_full_name</strong><strong>($keyword_short_name)</strong><br/>$keywordName</td>";
$count++;
}
echo '</table>';
echo "</div";
<script>
$('#keywordBox').click(function(e) {
var kid = $('#kid').val();
var cdid = $('#cdid').val();
e.preventDefault();
$.ajax({
type:"post",
url:"addKeywordProcess.php",
data:{
'kid' : kid,
'cdid' : cdid
},
success:function(res){
$('#result').html(res);
}
});
});
</script>
addKeywordProcess.php代碼:以$kid
<?php
ob_start();
@session_start();
require_once("../config.php");
if(!isset($_SESSION['front_username']) && isset($_SESSION['front_username']) == "" &&
!isset($_SESSION['front_password']) && isset($_SESSION['front_password']) == "" &&
!isset($_SESSION['user_id']) && isset($_SESSION['user_id']) == "") {
header("Location:login.php");
exit();
}
$cdid = (int) $_POST['cdid']; // Get cdid from keyword page.
$kid = (int) $_POST['kid']; // Get cdid from keyword page.
$check = mysql_query("SELECT cdid, kid FROM userkeywords WHERE kid = '$kid' AND cdid = '$cdid' ");
$num = mysql_num_rows($check);
if($num == 1){
echo "<div class='error'>Keyword already exits to your contact list. cdid = $cdid and kid = $kid </div>";
}else{
$query = mysql_query("INSERT INTO userkeywords (ukid, cdid, kid) VALUES ('', '$cdid', '$kid') ");
if($query){
echo "<div class='success'>Successfully added a new keyowrd to your contact list. </div>";
}else{
echo "<div class='error'>I can't added a new keyword. </div>";
}
}
?>
閱讀下面的答案,你的錯誤似乎是一個明顯的錯誤,這是由你的PHP和HTML代碼混合在一起,模糊。爲了將來的參考,您應該將HTML模板和PHP腳本分開,以使代碼更清晰,更易於閱讀。示例:http://stackoverflow.com/a/7368842/1031312 – Ozzy 2014-09-01 12:24:04
感謝@Ozzy重要指南。 – Shibbir 2014-09-01 12:25:09