的UIButton接受1個手指2的手指敲擊事件

保持遊戲得分，其中，所述遊戲點遞增/遞減的軌道我使用UIButton s到顯示在按鈕上的分數標籤，以1個手指的輕擊手勢將分數增加25，並以2個手指的輕擊手勢將分數遞減25。

我找不到更加模塊化的方式來編寫此代碼 ，每個按鈕可重複使用的唯一功能是：

func setButtonTitleAndIncrement(index: Int, button: UIButton) -> Int { 
    var index = index 
    index += 25 
    button.setTitle(String(index), for: .normal) 
    return index 
} 

func setButtonTitleAndDecrement(index: Int, button: UIButton) -> Int { 
    var index = index 
    index -= 25 
    button.setTitle(String(index), for: .normal) 
    return index 
}

但是對於每個按鈕，除了指定特定的按鈕和方法外，我必須使用相同的代碼，但我無法找出解決方法。 我喜歡採取一般index和button至少。有任何想法嗎？

var index1 = 0 
var index2 = 0 

override func viewDidLoad() { 
    super.viewDidLoad() 
    let oneFingerTapButtonTeam1 = UITapGestureRecognizer(target: self, action: #selector(incrementScoreTeam1)) 
    oneFingerTapButtonTeam1.numberOfTouchesRequired = 1 
    buttonTeam1.addGestureRecognizer(oneFingerTapButtonTeam1) 

    let twoFingerTapButtonTeam1 = UITapGestureRecognizer(target: self, action: #selector(decrementScoreTeam1)) 
    twoFingerTapButtonTeam1.numberOfTouchesRequired = 2 
    buttonTeam1.addGestureRecognizer(twoFingerTapButtonTeam1) 

    let oneFingerTapButtonTeam2 = UITapGestureRecognizer(target: self, action: #selector(incrementScoreTeam2)) 
    oneFingerTapButtonTeam2.numberOfTouchesRequired = 1 
    buttonTeam2.addGestureRecognizer(oneFingerTapButtonTeam2) 

    let twoFingerTapButtonTeam2 = UITapGestureRecognizer(target: self, action: #selector(decrementScoreTeam2)) 
    twoFingerTapButtonTeam2.numberOfTouchesRequired = 2 
    buttonTeam2.addGestureRecognizer(twoFingerTapButtonTeam2) 
} 

func incrementScoreTeam1() { 
    print("1 tapped") 
    let ind = setButtonTitleAndIncrement(index: index1, button: buttonTeam1) 
    index1 = ind 
} 

func incrementScoreTeam2() { 
    print("2 tapped") 
    let ind = setButtonTitleAndIncrement(index: index2, button: buttonTeam2) 
    index2 = ind 
} 

func decrementScoreTeam1() { 
    print("1 Two tapped") 
    let ind = setButtonTitleAndDecrement(index: index1, button: buttonTeam1) 
    index1 = ind 
} 

func decrementScoreTeam2() { 
    print("2 Two tapped") 
    let ind = setButtonTitleAndDecrement(index: index2, button: buttonTeam2) 
    index2 = ind 
}

來源

2017-02-23 SRMR

爲什麼你堅持有自帶的試圖超越事物的UIButton的，所有的併發症：沿線的的東西嗎？只需使用標籤和設計創建一個自定義UIView子類，並簡單地將手勢附加到它。不需要所有的模糊。 – 2017-02-23 21:35:15

@Sneak我沒有堅持任何事情，發佈問題以更好的方式，所以你的建議對我有意義。我剛開始時用UIButton認爲可能是最好的，但現在我正在重新思考。謝謝！ – SRMR

我明白了，帶着一個UIView子類，你將從頭開始擁有如此簡單的定製，而不是覆蓋東西並找到我建議的限制。 GL。 – 2017-02-23 21:56:56

如何繼承UIButton，然後添加索引作爲按鈕的屬性。

import UIKit 

@IBDesignable class BaseButton: UIButton { 

    var index = 0 

    required init?(coder aDecoder: NSCoder) { 
     super.init(coder: aDecoder) 
     setup() 
    } 

    override init(frame: CGRect) { 
     super.init(frame: frame) 
     setup() 
    } 

    override func prepareForInterfaceBuilder() { 
     super.prepareForInterfaceBuilder() 
     setup() 
    } 

    func setup() { 
     let oneFingerTapButtonTeam1 = UITapGestureRecognizer(target: self, action: #selector(incrementScoreTeam)) 
     oneFingerTapButtonTeam1.numberOfTouchesRequired = 1 
     addGestureRecognizer(oneFingerTapButtonTeam1) 

     let twoFingerTapButtonTeam1 = UITapGestureRecognizer(target: self, action: #selector(decrementScoreTeam)) 
     twoFingerTapButtonTeam1.numberOfTouchesRequired = 2 
     addGestureRecognizer(twoFingerTapButtonTeam1) 
    } 

    func incrementScoreTeam() { 
     let ind = setButtonTitleAndIncrement(index: index, button: self) 
     index = ind 
    } 

    func decrementScoreTeam() { 
     let ind = setButtonTitleAndDecrement(index: index, button: self) 
     index = ind 
    } 

    func setButtonTitleAndIncrement(index: Int, button: UIButton) -> Int { 
     var index = index 
     index += 25 
     button.setTitle(String(index), for: .normal) 
     return index 
    } 

    func setButtonTitleAndDecrement(index: Int, button: UIButton) -> Int { 
     var index = index 
     index -= 25 
     button.setTitle(String(index), for: .normal) 
     return index 
    } 
}

來源

2017-02-23 21:29:08 vj9

這是有道理的，謝謝你的整個答案！ – SRMR

的UIButton接受1個手指2的手指敲擊事件

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