搜索結果錯誤

Question

這是我的搜索查詢，如果沒有結果的比賽，我怎麼能顯示錯誤，請 幫助

$sql="SELECT * FROM course WHERE course_name LIKE '%" . $search_name . "%'"; 
       //-run the query against the mysql query function 
       $result=mysql_query($sql); 

Answer 1

$sql="SELECT * FROM course WHERE course_name LIKE '%" . $search_name . "%'"; 
       //-run the query against the mysql query function 
$result=mysql_query($sql); 

if(mysql_num_rows($result) < 1) 
{ 
    echo 'There were no results.'; 
} 

Answer 2

if(mysql_num_rows($sql)=="0") 
{ 
echo "----------------"; //your code here 
}