Symfony2 - 學說 - 從SQL到DQL

我正在研究基於Symfony2的PHP項目，我希望下面的這個教程能夠在Symfony2上工作，但實際上我通過使用「... FROM xx JOIN（SELECT .... 「：Symfony2 - 學說 - 從SQL到DQL

[Semantical Error] line 0, col 176 near '(
SELECT': Error: Class '(' is not defined.

，我想使工作的最後DQL語句是：

return $this->getEntityManager() 
       ->createQuery(
      "SELECT u.username, m1.id, n.id as notification, n.vue, u.lastActivity, LEFT(m1.message,60) as Message, m1.lu, m1.dateEnvoi, i.image 
      FROM MCoreBundle:Messages m1 
      JOIN (
       SELECT m.from, max(dateEnvoi) as dateEnvoi 
       FROM MCoreBundle:Messages m 
       JOIN MCoreBundle:User u on m.from = u.id 
       WHERE m.to = :user 
       GROUP BY m.from 
      ) t ON m1.from = t.from AND 
      m1.dateEnvoi = t.dateEnvoi, 
      MCoreBundle:User u, 
      MCoreBundle:Notification n, 
      MCoreBundle:Images i WHERE 
        u.id = m.from AND 
        n.id = m.notification AND 
        i.user = u.id") 
       ->setParameters(array('user' => $iIDUser)) 
       ->getResult();

實際的問題： 主義/ Symfony的犯規recorgnize的」 ... FROM XX加入（選擇....「

來源

2014-01-19 Youssef El Gharbaoui

你加入MCoreBundle：用戶U，MCoreBundle：通知N，MCoreBundle：圖片我。如果是的話，你必須在每次加入表格時寫入加入。 – sonam

嘗試過，但它並沒有真正解決我的問題，仍然得到相同的錯誤...'（SELECT'：錯誤：類'（'未定義。 –

試試這個

SELECT u.username, m1.id, n.id as notification, n.vue, u.lastActivity, LEFT(m1.message,60) as Message, m1.lu, m1.dateEnvoi, i.image 
FROM MCoreBundle:Messages m1, 
MCoreBundle:User u, 
MCoreBundle:Notification n, 
MCoreBundle:Images i 
JOIN (
    SELECT m.from, max(dateEnvoi) as dateEnvoi 
    FROM MCoreBundle:Messages m 
    JOIN MCoreBundle:User u on m.from = u.id 
    WHERE m.to = :user 
    GROUP BY m.from 
) t ON m1.from = t.from AND m1.dateEnvoi = t.dateEnvoi 
WHERE u.id = m.from AND n.id = m.notification AND i.user = u.id

來源

2014-01-19 01:51:12 sonam

仍然，同樣的問題，Symfony不喜歡「JOIN（... 「部分：/ –

Symfony2 - 學說 - 從SQL到DQL

回答

相關問題