獲取每週工作日的平均每週

我必須從下表中找出每週平均值（僅工作日 - 星期一至星期五）。我搜索的平均數是AVAI_NUM。我必須計算給定期間內每週的AVAI_NUM平均值。獲取每週工作日的平均每週

例子：如果期限爲2016年1月：

declare @dDateFrom date = cast('2016-01-01' as date) 
declare @dDateTo date = cast('2016-01-31' as date)

表看起來是這樣的：

declare @scavai table 
(
    avai_key int, 
    avai_dat date, 
    avai_num int 
)

填寫表格與數據：

insert into @scavai(avai_Key, avai_dat, avai_num) 
    select 1, cast('2016-01-01' as date), 3 
    union all 
    select 1, cast('2016-01-02' as date), 2 
    union all 
    select 1, cast('2016-01-03' as date), 5 
    union all 
    select 1, cast('2016-01-04' as date), 6 
    union all 
    select 1, cast('2016-01-05' as date), 1 
    union all 
    select 1, cast('2016-01-06' as date), 8 
    union all 
    select 1, cast('2016-01-07' as date), 4 
    union all 
    select 1, cast('2016-01-08' as date), 3 
    union all 
    select 1, cast('2016-01-09' as date), 2 
    union all 
    select 1, cast('2016-01-10' as date), 1 
    union all 
    select 1, cast('2016-01-11' as date), 9 
    union all 
    select 1, cast('2016-01-12' as date), 7 
    union all 
    select 1, cast('2016-01-13' as date), 3 
    union all 
    select 1, cast('2016-01-14' as date), 8 
    union all 
    select 1, cast('2016-01-15' as date), 3 
    union all 
    select 1, cast('2016-01-16' as date), 2 
    union all 
    select 1, cast('2016-01-17' as date), 3 
    union all 
    select 1, cast('2016-01-18' as date), 1 
    union all 
    select 1, cast('2016-01-19' as date), 4 
    union all 
    select 1, cast('2016-01-20' as date), 5 
    union all 
    select 1, cast('2016-01-21' as date), 7 
    union all 
    select 1, cast('2016-01-22' as date), 3 
    union all 
    select 1, cast('2016-01-23' as date), 3 
    union all 
    select 1, cast('2016-01-25' as date), 3 
    union all 
    select 1, cast('2016-01-26' as date), 3

我知道如何計算數量在特定時期內的週數：

select DATEDIFF(ww, '2016-01-01', '2016-01-31')

但是我不知道如何計算每週工作日的AVAI_NUM，並將其與特定周的天數相除，然後總結所有這些並用週數除？

來源

2017-03-11 FrenkyB

嘗試AVG（avai_num）以上（分區的日期部分（周，avai_dat）由avai_dat順序） – nazark

@nazark - 你可以請張貼這個作爲答案？（如果可能的話，整個查詢就是例子）。謝謝。 – FrenkyB

已發佈但不確定你要找的結果？ – nazark

嘗試，

select *, 
    AVG(cast(avai_num as decimal)) over 
    (partition by datepart(week, avai_dat) order by (select 1)) avg1 
    from @scavai 
    where avai_dat between @dDateFrom and @dDateTo 
    order by avai_dat

來源

2017-03-11 11:36:37 nazark

感謝您的回答，但結果在一週中的某天不同。每週的平均結果應該相同。 – FrenkyB

更新請立即嘗試。 – nazark

非常感謝，這工作。是否可以有平均值而不是整數的十進制結果？ AVAI_NUM是整數，但如果它是十進制（8,2），則平均值更準確。 – FrenkyB

獲取每週工作日的平均每週

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