這裏有多個塗鴉應用程序有一個撤消按鈕。我沒有實現這些,因爲我的代碼是不同的,但我已經看過這些概念。 I.E將點存儲在一個數組中。畫布不重繪圖像
當程序檢測到觸摸事件:
@Override
public boolean onTouchEvent(MotionEvent event) {
float touchX = event.getX(); //Gets the fingers x position
float touchY = event.getY(); //gets the fingers y position
PointF points = new PointF(); //init a new PointF
points.x = touchX; //store the coordinates in the Point object
points.y = touchY;
_pointList.add(points); //add this to the list of Points (array)
switch (event.getAction()){
case MotionEvent.ACTION_DOWN:
_path.moveTo(touchX, touchY); //Set the beginning of the next contour to the point (x,y)
//will start drawing from where the last point was
break;
case MotionEvent.ACTION_MOVE:
_path.lineTo(touchX, touchY);
break;
case MotionEvent.ACTION_UP:
break;
}
invalidate();
return true;
}
在理論上應該_pointList Array
捕獲所有的觸摸輸入秩序。這很明顯,因爲控制檯顯示數組的大小。
在onDraw
方法中,它應該循環遍歷a列表中的所有點。由於它包含用戶在屏幕上進行交互的所有點,因此理論上它應該從內存中繪製線條。
@Override
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
for (PointF points : _pointList) {
_path.moveTo(points.x, points.y);
_path.lineTo(points.x, points.y);
_canvas.drawPath(_path, _paint);
}
canvas.drawBitmap(_bitmap, 0, 0, _paint);
}
當應用程序運行時,我可以在屏幕上繪圖,並且由於清除方法屏幕清除。
public void clear(){
_pointList.clear();// empty the list that stores the points
_bitmap = Bitmap.createBitmap(1000,1000,
Bitmap.Config.ARGB_8888);
_canvas = new Canvas(_bitmap);
_path = new Path();
_paint = new Paint(Paint.DITHER_FLAG);
//Added later..
_paint.setColor(Color.RED);
_paint.setAntiAlias(true);
_paint.setStyle(Paint.Style.STROKE);
//empties the screen
invalidate();
}
然而,在我的Undo方法,它應該放棄從_pointList
列表中的點(包含用戶的X和Y觸摸輸入)之一。刪除點後,屏幕應重新繪製內存中的所有行。
public void undo() {
Log.d("Number", "undo:" + _pointList.size() );
if (_pointList.size()>0){
_bitmap = Bitmap.createBitmap(1000,1000,
Bitmap.Config.ARGB_8888);
_canvas = new Canvas(_bitmap);
_path = new Path();
_paint = new Paint(Paint.DITHER_FLAG);
//Added later..
_paint.setColor(Color.RED);
_paint.setAntiAlias(true);
_paint.setStyle(Paint.Style.STROKE);
_pointList.remove(_pointList.size() - 1);
invalidate();
}
}
此方法具有與「清除」方法相同的效果,並且不重繪線,
我的其他辦法,以撤銷按鈕是把位圖到一個數組,但我敢肯定這會導致內存問題,因爲它是一個動態程序。
問題:爲什麼'undo'方法中的'invalidate'調用不會更新屏幕?
更新:
整個代碼:
--Draw--
package com.example.moynul.myapplication;
import android.content.Context;
import android.graphics.Bitmap;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Path;
import android.graphics.Point;
import android.graphics.PointF;
import android.graphics.PorterDuff;
import android.util.AttributeSet;
import android.util.Log;
import android.view.MotionEvent;
import android.view.View;
import android.widget.Button;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
/**
* Created by moynu on 10/12/2015.
*/
public class Draw extends View {
private Paint _paint = new Paint();
private Path _path = new Path();
private Bitmap _bitmap;
private Canvas _canvas;
private List<PointF> _pointList = new ArrayList<PointF>();
public Draw(Context context) {
super(context);
init(null, 0);
}
public Draw(Context context, AttributeSet attrs) {
super(context, attrs);
init(attrs,0);
}
public Draw(Context context, AttributeSet attrs, int defStyleAttr) {
super(context, attrs, defStyleAttr);
init(attrs, defStyleAttr);
}
private void init(AttributeSet attrs, int defStyleAttr) {
_paint.setColor(Color.RED);
_paint.setAntiAlias(true);
_paint.setStyle(Paint.Style.STROKE);
_bitmap = Bitmap.createBitmap (1080, 1920, Bitmap.Config.ARGB_8888);
_canvas = new Canvas(_bitmap);
}
@Override
public boolean onTouchEvent(MotionEvent event) {
float touchX = event.getX(); //Gets the fingers x position
float touchY = event.getY(); //gets the fingers y position
PointF points = new PointF(); //init a new PointF
points.x = touchX; //store the coordinates in the Point object
points.y = touchY;
_pointList.add(points); //add this to the list of Points (array)
switch (event.getAction()){
case MotionEvent.ACTION_DOWN:
_path.moveTo(touchX, touchY); //Set the beginning of the next contour to the point (x,y)
//will start drawing from where the last point was
break;
case MotionEvent.ACTION_MOVE:
_path.lineTo(touchX, touchY);
break;
case MotionEvent.ACTION_UP:
break;
}
invalidate();
return true;
}
@Override
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
for (PointF points : _pointList) {
_path.moveTo(points.x, points.y);
_path.lineTo(points.x, points.y);
_canvas.drawPath(_path, _paint);
}
canvas.drawBitmap(_bitmap, 0, 0, _paint);
}
public void clear(){
_pointList.clear();// empty the list that stores the points
_bitmap = Bitmap.createBitmap(1000,1000,
Bitmap.Config.ARGB_8888);
_canvas = new Canvas(_bitmap);
_path = new Path();
_paint = new Paint(Paint.DITHER_FLAG);
//Added later..
_paint.setColor(Color.RED);
_paint.setAntiAlias(true);
_paint.setStyle(Paint.Style.STROKE);
//empties the screen
invalidate();
}
public void undo() {
Log.d("Number", "undo:" + _pointList.size());
if (_pointList.size()>0){
_pointList.remove(_pointList.size() - 1);
_bitmap = Bitmap.createBitmap(1000,1000,
Bitmap.Config.ARGB_8888);
_canvas = new Canvas(_bitmap);
_path = new Path();
_paint = new Paint(Paint.DITHER_FLAG);
//Added later..
_paint.setColor(Color.RED);
_paint.setAntiAlias(true);
_paint.setStyle(Paint.Style.STROKE);
invalidate();
}
}
}
請上傳全班同學的看法,這將有助於@RohitPatil的頁面已經更新,以顯示整個代碼在我結束 –
解決。 – Moynul
你需要重新思考你的邏輯。在'onDraw()'方法中,當迭代點來更新路徑時,首先'moveTo()'一個點,然後'lineTo()'同一點。這實際上什麼都不做,這就是爲什麼你的圖像在撤消之後變成空白。你能夠繪製的唯一原因是因爲你在'onTouchEvent()'中移動了Path。但是,在撤消操作中,您將重置路徑,所以下一個'onDraw()'只是循環遍歷點,對每個點都做同樣的「無」,但沒有在onTouchEvent中發生的路徑更新)'。 –