什麼不是這個代碼插入到SQLite數據庫的值？

我正在爲android編寫一個應用程序。我需要讀取一個txt文件並將數據寫入SQLite文件中。我設法完成了所有的代碼，但是它應該將值插入到數據庫中的部分不起作用。我給出了以下代碼：什麼不是這個代碼插入到SQLite數據庫的值？

try{ 
    ContentValues values = new ContentValues(); 
    values.put(KEY_NAME, firstNumber); // Contact Name 
    values.put(KEY_PH_NO, strfinal); // Contact Phone 
    // Inserting Row 
    db.insert(TABLE_CONTACTS, null, values); 
} catch(Exception e) { 
    e.printStackTrace(); 
}

此代碼未輸入數據庫中的值，並且在操作完成後數據庫保持爲空。這有什麼問題？謝謝。編輯：好的，這裏是全碼：

public class DatabaseHandler extends SQLiteOpenHelper { 

     // All Static variables 
     // Database Version 
     private static final int DATABASE_VERSION = 1; 

     // Database Name 
     private static final String DATABASE_NAME = "feedsmanager.sqlite"; 

     // Contacts table name 
     private static final String TABLE_CONTACTS = "table_to_hold_all_values"; 

     // Contacts Table Columns names 
     private static final String KEY_ID = "id"; 
     private static final String KEY_NAME = "name";//ctid 
     private static final String KEY_PH_NO = "phone_number";//feedname,address;feedname;address etc 
     Context ctx; 

     public DatabaseHandler(Context context) { 
      super(context, DATABASE_NAME, null, DATABASE_VERSION); 
      ctx=context; 
     } 

     // Creating Tables 
     @Override 
     public void onCreate(SQLiteDatabase db) { 

      //Log.d("in onCreate","twitch1"); 
      String CREATE_CONTACTS_TABLE = "CREATE TABLE " + TABLE_CONTACTS + "(" 
        + KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT," 
        + KEY_PH_NO + " TEXT);"; 

      //Log.d("below createcontacts","twitch1"); 
      try{ 
      db.execSQL(CREATE_CONTACTS_TABLE); 
      }catch(Exception e){Log.d("create went wrong: "+e,"twitch11");} 
      //Log.d("below db.execsql","twitch1"); 
      populate(db); 
    } 

      void populate(SQLiteDatabase dbs){ 
      String line=""; 


      try{ 
      InputStream is = ctx.getAssets().open("feedtitlesandaddresses.txt"); 
      InputStreamReader iz=new InputStreamReader(is); 
      BufferedReader br = new BufferedReader(iz); 
      //SQLiteDatabase dbs = this.getWritableDatabase(); 
      while((line=br.readLine())!=null) { 
       //Log.d("fcked here6","twitch1"); 
       StringTokenizer stringTokenizer = new StringTokenizer(line, "<"); 

       String firstNumber=""; 
       String strfinal=""; 
        firstNumber = (String) stringTokenizer.nextElement(); 
        **//Calculations to give values to firstNumber and strfinal excluded 

        ContentValues values = new ContentValues(); 

        values.put(KEY_NAME, firstNumber); // Contact Name 
        values.put(KEY_PH_NO, strfinal); // Contact Phone 
        // Inserting Row 

        dbs.insert(TABLE_CONTACTS, null, values);} 

       dbs.close();}catch(Exception e){Log.d("yeah error is"+e,"twitch12");} 
     }}

來源

2013-03-26 Ankit Rawat

你的logcat出現錯誤嗎？請張貼它。 – span 2013-03-26 21:14:51

@span不！我把它放在try catch塊中，沒有錯誤！ – 2013-03-26 21:15:55

@ user2213396：顯示你的'try/catch' – jlordo 2013-03-26 21:16:57