在Java中需要幫助（平均程序）

Question

我只是一名初學者程序員，我被困在我的部分代碼中;有沒有辦法告訴編譯器，如果用戶輸入7，它將通過1 2 3 4 5 6和7而不是僅使用7？

import java.util.Scanner; 
public class Average { 
    int tests; 
    int grade1, grade2, grade3, grade4, grade5, grade6, grade7, grade8, grade9, grade10; 
    int total; 
    double average; 
    public void Average1() { 

    Scanner input = new Scanner(System.in); 
    System.out.println("Enter how many tests you will use. (Minimum 3, Maximum 10.) "); 
    tests = input.nextInt(); 
    System.out.println("Enter the grade of your first test. (Do not include %)"); 
    grade1 = input.nextInt(); 
    System.out.println("Enter the grade of your second test. (Do not include %)"); 
    grade2 = input.nextInt(); 
    System.out.println("Enter the grade of your third test. (Do not include %)"); 
    grade3 = input.nextInt(); 
    switch (tests) { 

    case 4 : System.out.println("Enter the grade of your fourth test. (Do not include %)"); 
    grade4 = input.nextInt(); 
    break; 

    case 5 : System.out.println("Enter the grade of your fifth test. (Do not include %)"); 
    grade5 = input.nextInt(); 
    break; 

    case 6 : System.out.println("Enter the grade of your sixth test. (Do not include %)"); 
    grade6 = input.nextInt(); 
    break; 

    case 7 : System.out.println("Enter the grade of your seventh test. (Do not include %)"); 
    grade7 = input.nextInt(); 
    break; 

    case 8 : System.out.println("Enter the grade of your eighth test. (Do not include %)"); 
    grade8 = input.nextInt(); 
    break; 

    case 9 :System.out.println("Enter the grade of your ninth test. (Do not include %)"); 
    grade9 = input.nextInt(); 
    break; 

    case 10 : System.out.println("Enter the grade of your tenth test. (Do not include %)"); 
    grade10 = input.nextInt(); 
    break; 
    } 
    total = grade1 + grade2 + grade3; 
    average = total/tests; 
} 

}

在這個例子中，我試圖做一個基本的平均值計算。 （這只是一個類，其他代碼我在單獨的類中。）我需要詢問用戶他將輸入多少測試。 （它會自動通過1 - 3）所以，如果用戶輸入6個測試，我怎麼告訴編譯器不只是直接去6。我希望它通過1-6。人們說我需要使用for循環，但是我會在哪裏插入循環？

（請記住，我只是個初學者。）

Answer 1

您只需要使用循環來保持運行總數並使用循環來收集它們爲第一個問題指定的條目數。您可能需要爲以下內容添加一些錯誤檢查以處理錯誤的輸入（例如，爲測試次數輸入零）。

import java.util.Scanner; 
public class Average { 
    int tests; 
    int total = 0; 
    double average; 
    public void Average1() { 

     Scanner input = new Scanner(System.in); 
     System.out.println("Enter how many tests you will use. (Minimum 3, Maximum 10.) "); 
     tests = input.nextInt(); 
     for (int i = 1; i <= tests; ++i) { 
      System.out.println("Enter the grade of for test " + i + ". (Do not include %)"); 
      total += input.nextInt(); 
     } 

     average = total/tests; 
    } 
} 

Answer 2

創建一個簡單的循環，基於用戶輸入，如：

如果用戶輸入的是7，則：

for(int i = 1; i <= userInput; i++) { 
    // then pass the i value to your method, it will go through >> 1 2 3 4 5 6 7. 
} 

Answer 3

使用for環

for(int i = 0; i <=7 i++){ 
    //Code 

} 

Answer 4

這裏是我會怎麼處理這個問題，

// Note the method naming convention. Also, a return type. 
// takes an input Scanner and the number of tests. 
public static double average1(Scanner input, 
    int tests) { 
    // An array to store the grades. 
    int[] testGrades = new int[tests]; 
    long total = 0; 
    for (int i = 1; i <= tests; ++i) { 
    System.out.printf(
     "Enter the grade for test %d.\n", i); 
    System.out.flush(); 
    if (input.hasNextInt()) { 
     testGrades[i - 1] = input.nextInt(); 
    } 
    } 
    System.out.println("The array contains: " 
     + java.util.Arrays.toString(testGrades)); 
    System.out.flush(); 
    // Add up the grades for the total. This addition could occur at input. 
    for (int i : testGrades) { 
    total += i; 
    } 
    return total/tests; 
} 

public static void main(String[] args) { 
    Scanner input = new Scanner(System.in); 
    System.out.println("Please enter the # of tests to average: "); 
    System.out.flush(); 
    int testCount = input.nextInt(); 
    System.out.println("The average is: " 
     + average1(input, testCount)); 
}