需要幫助上平均的Python

Question

查找值的在該領域[定量]平均大於或等於（337） 這是定量字段

quant 
100 
7 
109 
204 
28 
292 
105 
254 
441 
401 
410 
14 
15 
51 
96 
403 
75 
31 
109 
17 

這是我試圖

代碼

import csv 

total = count = 0 

with open('3111111a.csv', newline='') as f: 
    reader = csv.reader(f) 
    next(reader, None) 

    for row in reader: 
     total += float(row[4]) 
     count += 1 

    if count: 
     average = total/count 
     print('The average of the values is {}'.format(average)) 

Answer 1

試試這個：

#!/bin/env python 
import csv 
from itertools import islice 

total = count = 0 

with open('3111111a.csv', newline='') as f: 
    reader = csv.reader(f) 
    # `isslice` will skip any header/title row. 
    # Generates a list of integers from the fourth CSV value 
    numbers = (int(row[4]) for row in islice(reader, 1, None)) 
    # Generates another list of values that are >= 337 
    gt337 = [i for i in numbers if i >= 337] 

# Sums all the numbers in our list then divides by the number to get the average 
print (sum(gt337)/len(gt337)) 

最高分使用with！

您可以從文檔中瞭解關於islice()和List Comprehensions的更多信息。

有樂趣Python :-)

Answer 2

這個「CSV」文件相當簡單，所以看起來並不需要使用CSV模塊。
i.strip().isdigit()跳過前導quant。

>>> [i for i in open("average.csv", "r")] 
['quant\n', '100\n', '7\n', '109\n', '204\n', '28\n', '292\n', '105\n', '254\n', '441\n', '401\n', '410\n', '14\n', '15\n', '51\n', '96\n', '403\n', '75\n', '31\n', '109\n', '17\n'] 
>>> l = [int(i.strip()) for i in open("average.csv", "r")\ 
...   if i.strip().isdigit() and int(i) >= 337] 
>>> l 
[441, 401, 410, 403] 
>>> sum(l)/float(len(l)) 
413.75 

我知道，這個列表理解現在已經變得非常複雜，它可能不是最好的解決方案了，但我會讓它留在萬一有人有興趣使用類似的東西。畢竟，這是最緊湊的解決方案，您不必使用額外的模塊。