在T-SQL生成隨機ID（固定長度）

Question

可能重複：
Generating random string in T-SQL

我需要轉換在T-SQL此C＃方法：

public static string GenerateRandomID(int size) 
    { 
     StringBuilder pass = new StringBuilder(); 
     Random random = new Random(); 
     for (int i = 0; i < size; i++) 
     { 
      int binary = random.Next(0, 2); 
      switch (binary) 
      { 
       case 0: 
        char ch = (Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)))); 
        pass.Append(ch); 
        break; 
       case 1: 
        int num = random.Next(1, 10); 
        pass.Append(num); 
        break; 
      } 
     } 
     return pass.ToString(); 
    } 

使用示例：string output = GenerateRandomID（15）

輸出應該是這樣的：O1REGVIDK7T4R9R

有人有一個想法......

Answer 1

create proc GenerateRandomID 
    @size  int 
as 
begin 

    declare @chars char(26) = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' 
    declare @i int = 0 
    declare @id varchar(max) = '' 

    while @i < @size 
    begin 
     if rand() > .5 
      set @id = @id + substring(@chars, cast(ceiling(rand() * 26) as int), 1) 
     else 
      set @id = @id + cast(floor(rand() * 10) as varchar(2)) 
     set @i = @i + 1 
    end 

    select @id 

end 
go 



exec GenerateRandomID 15 

------------------- 
BWZBKR601I8Z9KV 

(1 row(s) affected)