5
所以我不明白爲什麼會出現這個錯誤。是字段值「產品」數字？.. 我有UNION ALL查詢，它使第一行顯示其他行的總和。我的查詢時間很長，所以我不會發布它（但如果有必要，我會發布它）。PostgreSQL - DataError：數字類型的無效輸入語法：「Product」
所以首先我會給我的代碼片段：
with w as (
SELECT
...
CASE x.variants WHEN x.variants THEN x.product || ' - ' || x.variants else x.product END as product
...
)
SELECT
...
'Product' as product,
...
UNION ALL
SELECT * FROM w
所以我使用的產品列在第一行的「產品」（對，因爲我不需要在此字段來計算。第一行，但計算等領域總數）
當我運行我的查詢它輸出這樣的錯誤：
DataError: invalid input syntax for type numeric: "Product"
LINE 104: 'Product' as product,
編輯： 的PostgreSQL 8.4版
全面查詢：
(
with w as (SELECT
min(fld2.id) AS id, -- note. Posted code is working now, but this select part was not
fld2.partner as partner, -- the same that is at the bottom (where different first line
fld2.product as product, -- is queried. So that gave error.
fld2.qty1 as qty1,
fld2.qty2 as qty2,
fld2.q1 as q1,
fld2.q2 as q2,
CASE WHEN (q1 >= q2 and q2 != 0) THEN ((q1-q2)/q2) * 100 WHEN (q1=0 or q2=0) THEN NULL WHEN (q2 > q1 and q1!=0) THEN ((q1/q2)-1)*100 END as percent_q,
fld2.price_q as price_q,
fld2.y1 as y1,
fld2.y2 as y2,
CASE WHEN (y1 >= y2 and y2 != 0) THEN ((y1-y2)/y2) * 100 WHEN (y1=0 or y2=0) THEN NULL WHEN (y2 > y1 and y1!=0) THEN ((y1/y2)-1)*100 END as percent_y,
fld2. price_y as price_y
FROM
(
SELECT
min(x.id) AS id,
x.partner as partner,
--quarter as quarter,
CASE x.variants WHEN x.variants THEN x.product || ' - ' || x.variants else x.product END as product,
sum(case when (calcyear=DATE_PART('year', now()) and x.quarter=3) then x.qty else 0 end) as qty1,
sum(case when (calcyear=DATE_PART('year', now() - '1 year'::interval) and x.quarter=3) then x.qty else 0 end) as qty2,
sum(case when (calcyear=DATE_PART('year', now()) and x.quarter=3) then price_unit else 0 end) as q1,
sum(case when (calcyear=DATE_PART('year', now() - '1 year'::interval) and x.quarter=3) then price_unit else 0 end) as q2,
sum(case calcyear when DATE_PART('year', now()) then price_unit else 0 end) as y1,
sum(case calcyear when DATE_PART('year', now() - '1 year'::interval) then price_unit else 0 end) as y2,
sum(case when (calcyear=DATE_PART('year', now()) and x.quarter=3) then price_unit WHEN (calcyear=DATE_PART('year', now() - '1 year'::interval) and x.quarter=3) THEN -1*price_unit end) AS price_q,
sum(case when calcyear=DATE_PART('year', now()) then price_unit ELSE -1*price_unit end) AS price_y
FROM (
SELECT
min(so.id) as id,
DATE_PART('year', so.date_order) AS calcyear,
DATE_PART('quarter', so.date_order) AS quarter,
sol.price_unit as price_unit,
rp.name as partner,
pt.name as product,
pp.variants as variants,
sol.product_uom_qty as qty
FROM
sale_order AS so
INNER JOIN sale_order_line AS sol ON (sol.order_id = so.id)
INNER JOIN res_partner as rp ON (so.partner_id = rp.id)
INNER JOIN product_product as pp ON (sol.product_id=pp.id)
INNER JOIN product_template as pt ON (pp.product_tmpl_id=pt.id)
WHERE EXISTS(
SELECT * FROM res_partner_category_rel rpcl
WHERE
rpcl.partner_id=rp.id and rpcl.category_id=37
and (so.date_order >= date_trunc('year', now() - '1 year'::interval)::timestamp::date and so.date_order <= date_trunc('year', now()+ '1 year'::interval)::timestamp::date-1)
and rp.distributor=True and rp.active=True
and so.state != 'cancel'
)
GROUP BY
variants,
calcyear,
quarter,
price_unit,
partner,
product,
qty
) AS x
GROUP BY
partner,
x.variants,
x.product
ORDER BY
partner
)fld2
GROUP BY
partner,
q1,
q2,
y1,
y2,
qty1,
qty2,
product,
price_q,
price_y,
percent_q,
percent_y
ORDER BY
partner
)
SELECT
1111 as id,
'Viso' as partner,
'Product' as product,
sum(uf.qty1) as qty1,
sum(uf.qty2) as qty2,
sum(uf.q1) as q1,
sum(uf.q2) as q2,
sum(CASE WHEN (uf.q1 >= uf.q2 and uf.q2 != 0) THEN ((uf.q1-uf.q2)/uf.q2) * 100 WHEN (uf.q1=0 or uf.q2=0) THEN NULL WHEN (uf.q2 > uf.q1 and uf.q1!=0) THEN ((uf.q1/uf.q2)-1)*100 END) as percent_q,
sum(uf.price_q) as price_q,
sum(uf.y1) as y1,
sum(uf.y2) as y2,
sum(CASE WHEN (uf.y1 >= uf.y2 and uf.y2 != 0) THEN ((uf.y1-uf.y2)/uf.y2) * 100 WHEN (uf.y1=0 or uf.y2=0) THEN NULL WHEN (uf.y2 > uf.y1 and uf.y1!=0) THEN ((uf.y1/uf.y2)-1)*100 END) as percent_y,
sum(uf.price_y) as price_y
FROM
(
SELECT
sum(price_q) as price_q,
sum(price_y) as price_y,
sum(qty1) as qty1,
sum(qty2) as qty2,
sum(q1) as q1,
sum(q2) as q2,
sum(y1) as y1,
sum(y2) as y2
FROM w
)uf
UNION ALL
SELECT * FROM w
) fld
你可以發佈完整的SQL腳本嗎 – EdChum
好吧，明天我會發布它。 – Andrius
請始終*包含您的PostgreSQL版本以及您在問題中詢問的完整代碼。 –