如何向數組添加搜索功能？

Question

我需要添加一個函數來在字符串數組中搜索並調出帶有關聯電話號碼的用戶。雖然我輸了。任何創建的功能只會顯示沒有號碼的人員姓名。如果沒有找到，它需要說錯誤。

int main(int argc, char** argv) 
{ 
    int i, n, j; 
    string name[100]; 
    string phone[100]; 
    int index[100]; 

    cout << "How many names and phone numbers do you want to enter? " << endl 
     << "Entering 0 ends the program." << endl; 
    cin >> n; 

    if (n == 0) 
     return 0; 

    for (i = 0; i < n; i++) { 

     cout << "Please enter a name: "; 
     cin >> name[i]; 

     cout << "Please enter a phone number: "; 
     cin >> phone[i]; 
    } 

    for (i = 0; i < n; i++) { 
     index[i] = i; 
    } 

    for (i = 0; i < n; i++) { 

     for (j = i + 1; j < n; j++) { 
      int temp; 
      if (phone[index[i]] > phone[index[j]]) { 
       temp = index[i]; 
       index[i] = index[j]; 
       index[j] = temp; 
      } 
     } 
    } 
    cout << "These entries are in ascending order by phone number: " << endl; 
    cout << "Name" 
     << "   " 
     << "Phone Number" << endl; 
    for (i = 0; i < n; i++) { 

     cout << name[index[i]] << "    " << phone[index[i]] << endl; 
    } 

    return 0; 
} 

Answer 1

此代碼應爲你工作（如果我理解這個問題）

int search(string name[], string searchedName){ 
     for(int i=0; i<100; i++){ 
      if(searchedName == name[i]) 
       return i; //Returns the position of the person, which is also the index of his phone number 
     } 
     return -1; //If -1 is returned it means there is no such name an "searchedName" in the vector 
    } 

你可以調用這個函數像這樣

int main(){ 
     /* all the stuff you already have inside here */ 
    string nameToSearch; 
    cout<<"Insert the name of the person you want to see the number of"<<endl; 
    cin>>nameToSearch; 
    int position = search(name, nameToSearch); 
    if(position == -1) 
     cout<<"Sorry, "<<nameToSearch<<" is not in our list"<<endl; 
    else 
     cout<<"The phone number of "<<nameToSearch<<" is "<<phone[position]<<endl; 

    return 0; 
} 

當然，這是非常基本的，你可以讓它變得更好，希望它有幫助！