如何處理上的按鈕

Question

我在做一個樣品的Android項目撥號鍵盤多點觸控，因此如果用戶按下任意號碼，我必須抓住這個值，這樣，如果用戶按下的時候，我怎麼能抓住兩個按鈕值的兩個按鈕使用觸摸事件

Answer 1

見Making Sense of Multitouch，這是一個非常好的文章這對我幫助很大。

基本上你需要重寫onTouch您的按鈕像

private static final int INVALID_POINTER_ID = -1; 

// The ‘active pointer’ is the one currently moving our object. 
private int mActivePointerId = INVALID_POINTER_ID; 

// Existing code ... 

@Override 
public boolean onTouchEvent(MotionEvent ev) { 
    final int action = ev.getAction(); 
    switch (action & MotionEvent.ACTION_MASK) { 
    case MotionEvent.ACTION_DOWN: { 
     final float x = ev.getX(); 
     final float y = ev.getY(); 

     mLastTouchX = x; 
     mLastTouchY = y; 

     // Save the ID of this pointer 
     mActivePointerId = ev.getPointerId(0); 
     break; 
    } 

    case MotionEvent.ACTION_MOVE: { 
     // Find the index of the active pointer and fetch its position 
     final int pointerIndex = ev.findPointerIndex(mActivePointerId); 
     final float x = ev.getX(pointerIndex); 
     final float y = ev.getY(pointerIndex); 

     final float dx = x - mLastTouchX; 
     final float dy = y - mLastTouchY; 

     mPosX += dx; 
     mPosY += dy; 

     mLastTouchX = x; 
     mLastTouchY = y; 

     invalidate(); 
     break; 
    } 

    case MotionEvent.ACTION_UP: { 
     mActivePointerId = INVALID_POINTER_ID; 
     break; 
    } 

    case MotionEvent.ACTION_CANCEL: { 
     mActivePointerId = INVALID_POINTER_ID; 
     break; 
    } 

    case MotionEvent.ACTION_POINTER_UP: { 
     // Extract the index of the pointer that left the touch sensor 
     final int pointerIndex = (action & MotionEvent.ACTION_POINTER_INDEX_MASK) 
       >> MotionEvent.ACTION_POINTER_INDEX_SHIFT; 
     final int pointerId = ev.getPointerId(pointerIndex); 
     if (pointerId == mActivePointerId) { 
      // This was our active pointer going up. Choose a new 
      // active pointer and adjust accordingly. 
      final int newPointerIndex = pointerIndex == 0 ? 1 : 0; 
      mLastTouchX = ev.getX(newPointerIndex); 
      mLastTouchY = ev.getY(newPointerIndex); 
      mActivePointerId = ev.getPointerId(newPointerIndex); 
     } 
     break; 
    } 
    } 

    return true; 
}