我正在嘗試編寫RPS遊戲。以下是我的代碼。在Rstudio中運行它沒有任何反應,但是在基本的R中,我在第29行中得到了一個評估錯誤,「缺少需要真/假的值」,並且這些繪圖也得到了不等價的x,y軸錯誤。必須有一些簡單的東西我錯過了爲什麼只有如果是錯誤的。謝謝你的時間。if函數中的評估錯誤。還在代碼中繪製錯誤。在R
Np<-1200 #pop size
Ng<-300 #generation time
P<-matrix(data=NA, nrow=Np/2, ncol=2) #matrix of pop
strategy=c('Ro','Pa','Sc')
P1<-sample(strategy, size=Np, replace=TRUE, prob=c(1/3,1/3,1/3)) #pop with equal probs of any strategy
# "res <- matrix(P1, nrow=Ng, ncol=3) #matrix for results" # defunct remove!
fR=c()
fP=c()
fS=c()
# result vectors for each strategy
# res<-matrix(NA, ng,3) # matrix as per example. results vectors returned null.
pR<- 0.5
pP<- 0.5
pS<- 0.5
# probabilities of success in each encounter of pX winning.
for(i in 1:Ng) {
for(j in 1:(Np/2)){
if(P[j,1]=='Ra'& P[j,2]=="Sc"& runif(1)<pR){P[j,2]<-"Ra"
}
if(P[j,1]=='Pa'& P[j,2]=="Sc"& runif(1)<pS){P[j,1]<-"Sc"
}
if(P[j,1]=='Sc'& P[j,2]=="Ra"& runif(1)<pR){P[j,1]<-"Ra"
}
if(P[j,1]=='Ra'& P[j,2]=="Pa"& runif(1)<pP){P[j,1]<-"Pa"
}
if(P[j,1]=='Pa'& P[j,2]=="Ra"& runif(1)<pP){P[j,2]<-"Pa"
}
if(P[j,1]=='Sc'& P[j,2]=="Pa"& runif(1)<pS){P[j,2]<-"Sc"
}
} # each row fights and winner replaces with appropriate probability.
P[,2]<-sample(P[,2]) #randomise interactions
fR=c(fR, sum(P=="Ra"))
fP=c(fP, sum(P=="Pa"))
fS=c(fS, sum(P=="Sc"))
}
plot(x=fR,y=Ng, ylab="frequency", xlab="Generation", col="black", type="l")
lines(fP, Ng, col="green")
lines(fS, Ng, col="red")
我認爲,所有你需要做的就是填充您的矩陣一旦通過所有的if語句去了。 – N8TRO 2013-02-18 17:35:57
非常感謝您的幫助。 – Sanalphatau 2013-02-18 18:24:31