組成的命令，在bash

Question

超時參數，我可以使用超時爲：

timeout 5s sleep 6s 

但我怎麼能傳遞給更多的超時複雜的命令？我試過以下，但所有給我的錯誤：幾乎立即

timeout 5s sleep 6s && echo "You did not fit in timeout" 
timeout 5s 'sleep 6s && echo "You did not fit in timeout"' 
timeout 5s {sleep 6s && echo "You did not fit in timeout"} 
timeout 5s (sleep 6s && echo "You did not fit in timeout") 

Answer 1

看一看這樣的：

$ timeout 5 sleep 2 && echo OK || echo "You did not fit in timeout" 
OK 
$ timeout 1 sleep 2 && echo OK || echo "You did not fit in timeout" 
You did not fit in timeout 

Answer 2

張貼後，我想通了：

timeout 5s sh -c 'sleep 6s && echo "You did not fit in timeout"' 

有沒有更好的解決辦法？