錯誤DO循環：預期在（1）

Question

在表達一個右括號在編譯使用Windows代碼::塊16.0.1這個代碼，示出了以下錯誤

a(i) = (1/(delx)^2)-(1/x-1) 
       1 
Error: Expected a right parenthesis in expression at (1) 

b(i) = ((-2/((delx)^2)) - bi*ce) 
        1 
Error: Expected a right parenthesis in expression at (1) 

c(i) = (1/(delx)^2) + (1/(2*(delx)*(x-1))) 
       1 
Error: Expected a right parenthesis in expression at (1) 

論加法& 3個語句中的每一個的結尾，後面的2成爲好的，但第一個保持不變

program HW0 
implicit none 
integer, parameter :: nx=101 
integer, parameter :: ce = 100 
real*8, parameter :: bi = 10.d0 
real*8 :: delx 
integer :: i 
real*8, dimension(nx) :: t, x 
real*8, dimension(nx) :: a, b, c, d 
i = 1 
delx = 1/(nx-1) 


a(1) = 0; b(1) = 1; c(1) = 0; d(1) = 0 
a(nx) = -(1/(delx)) 
b(delx) = (1/(delx)) + bi 
c(nx) = 0; d(nx) = 0; 

do i = 2, (nx - 1) 
a(i) = (1/(delx)^2)-(1/x-1) 
b(i) = ((-2/((delx)^2)) - bi*ce) 
c(i) = (1/(delx)^2) + (1/(2*(delx)*(x-1))) 
d(i) = 0 
enddo 

do i = 2, nx 
b(i) = b(i) - c(i-1)*(a(i)/b(i-1)); d(i) = d(i) - d(i-1)*(a(i)/b(i-1)) 
enddo 

t(nx) = d(nx)/b(nx) 

do i = (nx-1), 1, -1 
t(i) = (d(i) - c(i)*t(i+1))/b(i) 
enddo 
stop 
end program HW0 

Answer 1

^不是Fortran運算符。你要 **。