查詢兩個日期和另一個數據

Question

我需要在兩個日期（例如1年）之間按名稱顯示房子。我嘗試了以下請求，但它不起作用。

SELECT * 
FROM DATA1 
WHERE facility='house' 
    AND datee BETWEEN '2014-02-01' AND '2015-02-31' 
GROUP BY name 
ORDER BY datee ASC; 

Answer 1

這是解決方案！

SELECT * 
FROM DATA1 
WHERE facility= 'house' 
AND datee BETWEEN '2014-02-01' AND '2015-02-28' 
ORDER BY facility,datee ASC 

Answer 2

試試這個，它可能會幫助你。

SELECT * FROM DATA1 
WHERE facility= 'house' 
AND (dateE BETWEEN YEAR(2014-02-01) AND YEAR(2015-02-31)) 
GROUP BY name ORDER BY datee ASC; 

Answer 3

嗨，你可以用這些

SELECT * FROM DATA WHERE facility= 'house' 
AND(From_date >= '2013-01-03' AND To_date <= '2013-01-09') 
GROUP BY name 
ORDER BY datee ASC; 

Answer 4

這走的是解決方案可以對你有所幫助。

SELECT * 
FROM DATA1 
WHERE facility= 'house' 
    AND (cast(datee as date)) BETWEEN (cast('2014-02-01' as date) AND cast('2015-02-28' as date)) 
ORDER BY name, datee ASC;