從動態帖子名稱上的用戶接收多個輸入

Question

請檢查下面的代碼。我需要把每個產品數量值輸入表格用戶。但產品/ ID是動態的並且來自數據庫。我如何接收和識別哪些產品的數量值將由用戶提交？我的意思是因爲產品是多重/動態來形式數據庫，所以我不能通過$ _POST ['ID']得到他們。那麼這種情況下的解決方案呢？

<form method="post"> 
<table class="table table-hover"> 
    <thead> 
    <tr> 
     <th>Stock Available</th> 
     <th>Product Name</th> 
     <th>Enter Order Quantity</th> 
    </tr> 
    </thead> 
    <tbody> 

<?php 
$q= mysqli_query($conn,"SELECT * FROM products"); 
while ($row=mysqli_fetch_array($q)) { 
    $id = $row['id']; 
    $product_name = $row['product_name']; 
    $available_stock = $row['available_stock']; 
    echo ' 
<tr> 
<td>'.$available_stock.'</td> 
<td>'.$product_name.'</td> 
<td><input type="number" min="1" class="form-control" name="qty[]"></td> 
<input type="hidden" name="id[]" value="'.$id.'"> 
<tr> 
'; 
} 

?> 
    </tbody> 
</table><br><br> 
<button type="submit" class="btn btn-success" name="submit_next_order2">Confirm This Order</button> 

</form> 

Answer 1

<?php 

if($_POST['submit_next_order2']) 
{ 
print_R($_POST);die; 
} 

？> 請更新您的HTML。

<?php 
$q= mysqli_query($conn,"SELECT * FROM products"); 
while ($row=mysqli_fetch_array($q)) { 
    $id = $row['id']; 
    $product_name = $row['product_name']; 
    $available_stock = $row['available_stock']; 
    echo ' 
    <tr> 
    <td>'.$available_stock.'</td> 
     <td>'.$product_name.'</td> 
     <td><input type="number" min="1" class="form-control" name="qty['.$id .'][]"></td> 
     <input type="hidden" name="id['.$id .'][]" value="'.$id.'"> 
     <tr> 
     '; 
    } 

    ?>