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我寫了下面的代碼。我希望該函數返回矩陣D & S,但此時它只是返回等於S的矩陣'ans'。任何建議將不勝感激。謝謝。帶兩個輸出的寫入功能
function [D,S] = sdQRS(QRS_cell)
%scales & dilates QRS complexes
m = length(QRS_cell{1}(:,1));
n = length(QRS_cell);
d1 = linspace(0.5,1.0,10);
d2 = linspace(1.0,2.0,21);
d = vertcat(d1',(d2(2:21))');
s1 = linspace(0.6,1.0,13);
s2 = linspace(1.0,1.5,18);
s = vertcat(s1',(s2(2:18))');
DIL = cell(n,1);
SCAL = cell(n,1);
for i = 1:n
DIL{i} = zeros(m,length(d));
SCAL{i} = zeros(m,length(d));
for j = 1:length(d)
DIL{i}(:,j) = interp1(QRS_cell{i}(:,1),QRS_cell{i}(:,2),QRS_cell{i}(:,1)/d(j),'linear','extrap');
SCAL{i}(:,j) = s(j)*QRS_cell{i}(:,2);
end
end
D = zeros(n);
S = zeros(n);
for k = 1:n
for l = 1:n
e = [];
t = [];
for a = 1:length(d)
e(a) = euc_dilQ(QRS_cell{k},QRS_cell{l},d(a));
t(a) = euc_scalQ(QRS_cell{k},QRS_cell{l},s(a));
end
[M,E] = min(e);
[M,T] = min(t);
D(k,l) = d(E);
S(k,l) = s(T);
end
end
在我看來調用該函數,它始終是一個可怕的設計決定允許的功能返回單獨的對象。我強烈建議(如果你必須堅持使用matlab)而不是'foo = myfunc(x)'並且在內部設置'foo.D = D; foo.S = S' –