不可編譯的源代碼：錯誤的Sym錯誤

Question

我一直在尋找解決這個問題的方法，無法找到任何我理解的東西。我正在做一個教程，並抄寫我老師輸入的所有東西，所以我只是在學習......但是當我這樣做時，它一直給我這個錯誤。由於我是新來這個，我不知道究竟發生了什麼意思或如何解決它:(

public final class DefaultPlayerNameConverter 
     implements PlayerNameConverter 
{ 

    /** 
    * Must be created through the create method. 
    */ 
    private DefaultPlayerNameConverter() 
    { 
    } 

    /** 
    * Create a DefaultPlayerNameConverter. 
    * 
    * @return a DefaultPlayerNameCOnverter. 
    */ 
    public static DefaultPlayerNameConverter create() 
    { 
     final DefaultPlayerNameConverter converter; 

     converter = new DefaultPlayerNameConverter(); 

     return (converter); 
    } 

    /** 
    * Convert player name to remove leading/trailing whitespace. 
    * 
    * @param name the name to convert. 
    * 
    * @return the converted name. 
    * 
    * @throws IllegalArgumentException if name is null. 
    */ 
    @Override 
    public String convertName(final String name) 
    { 
     final String convertedName; 

     if(name == null) 
     { 
      throw new IllegalArgumentException("name cannot be null"); 
     } 

     convertedName = name.trim(); 

     return (convertedName); 
    } 
} 

---

public class DefaultPlayerNameConverterTest { 

    public DefaultPlayerNameConverterTest() { 
    } 

    /** 
    * Test bad arguments to the convertName method. 
    */ 
    @Test 
    public void testConvertBadName() 
    { 
     try 
     { 
      new DefaultPlayerNameConverter.create().convertName(null); 
      fail("convertName(null) must throw an " 
        + "IllegalArgumentException"); 
     } 
     catch(final IllegalArgumentException ex) 
     { 
      assertEquals("name cannot be null", ex.getMessage()); 
     } 
    } 

     /** 
     * Test good arguments to the convertName method. 
     */ 
     @Test 
     public void testConvertGoodName() 
     { 
      checkConvertName("", ""); 
      checkConvertName("\t", ""); 
      checkConvertName("\n", ""); 
      checkConvertName("\r", ""); 
      checkConvertName("\r\n", ""); 
      checkConvertName("\r\n\t", ""); 
      checkConvertName("X", "X"); 
      checkConvertName(" X", "X"); 
      checkConvertName("X ", "X"); 
      checkConvertName(" X ", "X"); 
      checkConvertName("X Y", "X Y"); 
      checkConvertName("Hello\tworld", "Hello\tworld"); 
     } 
     /** 
     * Check that the name conversion works. 
     * 
     * @param originalName the name to convert. 
     * @param expectedName what the name should be converted to. 
     */ 
     private void checkConvertName(final String originalName, 
             final String expectedName) 
     { 
      final PlayerNameConverter converter; 
      final String convertedName; 

      converter = new DefaultPlayerNameConverter.create(); 
      convertedName = converter.convertName(originalName); 
      assertEquals(expectedName, convertedName); 

     } 
} 

錯誤不斷顯示在我的測試類，當我添加了「 DefaultPlayerNameConverter創造」的方法。我不知道如何解決它。我只是把什麼教程告訴我做。

---

這是PlayerNameConverter接口...

public interface PlayerNameConverter { 

    /** 
    * Convert the supplied name. 
    * 
    * @param name the name to convert. 
    * 
    * @return the converted name. 
    */ 
    String convertName(String name); 
} 

Answer 1

這條線：

new DefaultPlayerNameConverter.create().convertName(null); 

不應該有new關鍵字，它應該只是

DefaultPlayerNameConverter.create().convertName(null);