2
| userid | fullname |
| 1 | admin |
| 2 | jimmy |
| 3 | anton |
| 4 | steven |
表:MASCHINEN
| maschine | maschine-name |
| 1 | M1 |
| 2 | M2 |
| 3 | M3 |
| 4 | M4 |
表:vorrichtungen
| id | maschine | vorrichtung | createdby | datecreated | updatedby | dateupdated |
| 1 | 1 | 11111 | 1 | 2012-06-23 17:10:25 | 1 | 2012-06-23 18:15:20 |
| 2 | 1 | 22222 | 1 | 2012-06-25 07:50:49 | 0 | 0000-00-00 00:00:00 |
| 3 | 2 | 33333 | 2 | 2012-06-27 10:22:29 | 0 | 0000-00-00 00:00:00 |
| 4 | 3 | 44444 | 2 | 2012-06-28 09:41:27 | 1 | 2012-06-28 12:40:37 |
| 5 | 4 | 11111 | 3 | 2012-06-29 15:53:47 | 0 | 0000-00-00 00:00:00 |
| 6 | 4 | 33333 | 4 | 2012-06-29 22:30:02 | 2 | 2012-06-29 22:30:02 |
我的查詢看起來像這樣:
SELECT
vorrichtungen.`id`,
maschinen.`maschine-name` AS maschine,
vorrichtungen.`vorrichtung`,
vorrichtungen.`createdby`,
user.`fullname` AS creator,
vorrichtungen.`datecreated`,
vorrichtungen.`updatedby`,
vorrichtungen.`dateupdated`
FROM
vorrichtungen,maschinen,user
WHERE
maschinen.`maschine` = vorrichtungen.`maschine`
AND
vorrichtungen.`createdby` = user.`userid`
,我收到這樣的結果:
| id | maschine | vorrichtung | createdby | creator | datecreated | updatedby | dateupdated |
| 1 | M1 | 11111 | 1 | admin | 2012-06-23 17:10:25 | 1 | 2012-06-23 18:15:20 |
| 2 | M1 | 22222 | 1 | admin | 2012-06-25 07:50:49 | 0 | 0000-00-00 00:00:00 |
| 3 | M2 | 33333 | 2 | jimmy | 2012-06-27 10:22:29 | 0 | 0000-00-00 00:00:00 |
| 4 | M3 | 44444 | 2 | jimmy | 2012-06-28 09:41:27 | 1 | 2012-06-28 12:40:37 |
| 5 | M4 | 11111 | 3 | anton | 2012-06-29 15:53:47 | 0 | 0000-00-00 00:00:00 |
| 6 | M4 | 22222 | 4 | steven | 2012-06-29 22:30:02 | 2 | 2012-06-29 22:30:02 |
我試圖解釋我想要什麼..
如果updatedby = 0比從表用戶AS更新其他選擇全名0或類似的東西..但我想所有6行
我希望收到這樣的結果:
| id | maschine | vorrichtung | createdby | creator | datecreated | updatedby | updatetor | dateupdated |
| 1 | M1 | 11111 | 1 | admin | 2012-06-23 17:10:25 | 1 | admin | 2012-06-23 18:15:20 |
| 2 | M1 | 22222 | 1 | admin | 2012-06-25 07:50:49 | 0 | 0 | 0000-00-00 00:00:00 |
| 3 | M2 | 33333 | 2 | jimmy | 2012-06-27 10:22:29 | 0 | 0 | 0000-00-00 00:00:00 |
| 4 | M3 | 44444 | 2 | jimmy | 2012-06-28 09:41:27 | 1 | admin | 2012-06-28 12:40:37 |
| 5 | M4 | 11111 | 3 | anton | 2012-06-29 15:53:47 | 0 | 0 | 0000-00-00 00:00:00 |
| 6 | M4 | 22222 | 4 | steven | 2012-06-29 22:30:02 | 2 | jimmy | 2012-06-29 22:30:02 |
是有可能實現嗎? 感謝您的幫助:)
問候貝爾尼
我不會假設用戶在u.userid = v.updatedby上,其中0在內連接中可用。一個左連接+測試null和0是否更好? –
嗨Clodoaldo ...同樣在這裏..我只收到ID 1,4,6 ...但我想要所有:D – bernte
@bernte嘗試編輯的版本。 –