SQL查詢一天中的幾小時

Question

我有一個SQL Server 2008數據庫，其中有一個表（datetime數據類型），當下訂單時記錄。

我想運行一個查詢，該查詢將給出任何給定日期或日期範圍內每小時訂單總數的細目，但我不確定寫入查詢的最佳方式。

Answer 1

它應該是沿着線的東西：

SELECT DATEPART(HOUR, OrderDate) AS [Hour], COUNT(*) AS [Count] 
FROM [Orders] 
WHERE OrderDate BETWEEN @StartDate AND @EndDate --or whatever criteria 
GROUP BY DATEPART(HOUR, OrderDate) 

Answer 2

你可能尋找類似：

;WITH OrdersPerHour AS 
(
    SELECT 
     CAST(OrderDate AS DATE) 'OrderDate', 
     DATEPART(HOUR, OrderDate) AS 'Hour', 
     SalesAmount 
    FROM 
     dbo.YourOrderTable 
) 
SELECT 
    OrderDate, Hour, 
    COUNT(*),   -- number of orders 
    SUM(SalesAmount) -- sum of the amounts for those orders 
FROM 
    OrdersPerHour 
WHERE 
    OrderDate = '20120113' -- or whatever you're looking for 
GROUP BY 
    OrderDate, Hour 

不知道你指的是訂單金額的總和 - 或訂單數 - 當你說擊穿每個訂單的總量小時 - 如果您需要計數，只需使用COUNT(*)而不是SUM(SalesAmount)我放入我的查詢。

Answer 3

您可以使用DATEPART和GROUP BY得到這個：

SELECT DATEPART(Hour, DateField), COUNT(*) 
FROM Orders 
WHERE Date = @DateParam -- or your range check here 
GROUP BY DATEPART(Hour, Datefield) 

Answer 4

我相信這會是這麼簡單：

SELECT 
     [Hour] = DATEPART(HOUR,DateTimeField) 
     ,Orders = COUNT(*) 
    FROM 
     tblORDERS 
    GROUP BY 
     DATEPART(HOUR,DateTimeField)