PHP simpleImage類捕獲異常錯誤

Question

SimpleImage類未捕獲異常的時候，這裏負荷的形象是代碼：

public function load($filename) { 
     //echo $filename; exit; 
    $image_info = getimagesize($filename); 
    $this->image_type = $image_info[2]; 

    if ($this->image_type == IMAGETYPE_JPEG) { 
     $this->image = imagecreatefromjpeg($filename); 
    } elseif ($this->image_type == IMAGETYPE_GIF) { 
     $this->image = imagecreatefromgif($filename); 
    } elseif ($this->image_type == IMAGETYPE_PNG) { 
     $this->image = imagecreatefrompng($filename); 
    } 
} 

Answer 1

你是不是捕捉異常的最後一個人會被捕獲異常，如果它不符合條件。這裏是更新的代碼。

public function load($filename) { 
     //echo $filename; exit; 
    $image_info = getimagesize($filename); 
    $this->image_type = $image_info[2]; 

    if ($this->image_type == IMAGETYPE_JPEG) { 
     $this->image = imagecreatefromjpeg($filename); 
    } elseif ($this->image_type == IMAGETYPE_GIF) { 
     $this->image = imagecreatefromgif($filename); 
    } elseif ($this->image_type == IMAGETYPE_PNG) { 
     $this->image = imagecreatefrompng($filename); 
    } else { 
     throw new Exception("The file you're trying to open is not supported"); 
    } 
} 

我認爲這將解決。