如何通過雙方的名字和姓氏

Question

搜索我做一個搜索屏幕（搜索名單）在我的iPhone應用程序，在那裏我需要雙方的姓氏和名字

說我的搜索搜索tableview中包含的名字，像如下

Ravi Kiran 
sujay huilgol 
harry potter 

我的搜索工作，即只有名字，如果我搜索鐳它生病顯示拉維·基蘭但是當我搜索基蘭其不顯示鐳六基蘭

我filterContentForSearchText是這樣

- (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope 
{ 
    [self.arrSearhResults removeAllObjects]; // First clear the filtered array. 

    // Search the main list for Usenames whose type matches searchText; add items that match to the filtered array. 

    for(NSString * strUserName in arrUserInfo) 
    { 
     NSComparisonResult result = [strUserName compare:searchText options:(NSLiteralSearch|NSDiacriticInsensitiveSearch) range:NSMakeRange(0, [searchText length])]; 
     if (result == NSOrderedSame) 
     { 
      // Update the filtered array based on the search text and scope. 
      [self.arrSearhResults addObject:strUserName]; 
      //NSLog(@"arrSearhResults %@",arrSearhResults); 
     } 
    } 

} 

可能有人幫助我，請..... thanx提前！

Answer 1

使用rangeOfString搜索整個字符串

for(NSString * strUserName in arrUserInfo) 
{ 
    NSRange range = [strUserName rangeOfString:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)]; 
    if (range.length > 0) 
    { 
    [self.arrSearhResults addObject:strUserName]; 
    } 
} 

Answer 2

NSArray *array = [[NSArray alloc] initWithObjects:@"Ravi Kiran", @"sujay huilgol", nil]; 
for (NSString* name in array) 
{ 
    if ([name rangeOfString:@"Kiran"].location != NSNotFound) 
     NSLog(@"%@", name); 
} 

Answer 3

試試這個：

for(NSString * strUserName in arrUserInfo) 
{ 
    NSRange titleResultsRange = [[NSString stringWithFormat:@"%@",strUserName] rangeOfString:searchText options:NSCaseInsensitiveSearch]; 
    if (titleResultsRange.length){ 
     [self.arrSearhResults addObject:[self.contacts objectAtIndex:i]]; 
    } 
}