我想實現一個模板單鏈表,我是相當新的C++麻煩實施模板單鏈表
#include <iostream>
#include <string>
#define NEWL "\n"
#define PRINT(s) std::cout << s
#define PRINTL(s) std::cout << s << NEWL
#define PRINTERR(e) std::cerr << e << NEWL
////// Class for a Node
template<class Data> class Node {
Node<Data>* next_ptr;
Data data;
public:
Node(Node<Data>* nxt_ptr) :next_ptr(nxt_ptr) {};
Node(Data d, Node<Data>* nxt_ptr) :data(d), next_ptr(nxt_ptr) {};
Node<Data>* get_next() { return next_ptr; }
Data& get_data() { return data; }
friend std::ostream& operator<<(std::ostream& out, const Node<Data>& node) {
out << node.data;
return out;
};
};
////// Class for a SinglyLinkedList
template<class Data> class SLinkedList {
Node<Data>* head_ptr;
int max_size;
public:
SLinkedList() : head_ptr(nullptr) {};
bool is_empty() {
return head_ptr == nullptr;
};
bool is_full() {
return get_size() == max_size;
};
int get_size() {
if (is_empty()) {
return 0;
}
int count = 0;
for (Node<Data>* it_ptr = head_ptr; it_ptr != nullptr; it_ptr = it_ptr->get_next()) {
count++;
}
return count;
};
void add(Data d) {
if (is_full()) {
throw std::exception("List is full!");
}
Node<Data> new_node(d, head_ptr);
head_ptr = &new_node;
};
void print_content() {
int count = 1;
PRINTL("This list contains:");
for (Node<Data>* it_ptr = head_ptr; it_ptr != nullptr; it_ptr = it_ptr->get_next()) {
PRINTL("\t["<< count << "]" << " at " << it_ptr << " : " << *it_ptr);
count++;
}
}
};
////// Main function
int main()
{
SLinkedList<int> sll;
sll.add(42);
sll.print_content();
}
我不能得到這個工作。以某種方式迭代for循環列表不起作用。它總是導致閱讀訪問衝突異常關於指向0xCCCCCCD0
的指針,我不知道如何解決這個問題。
我想提一下(即使已經有一個很好的答案),「0xCCCCCCD0」接近魔術調試代碼。看起來像微軟調試運行時正在告訴你,你正在使用未初始化的堆棧內存:http://stackoverflow.com/a/127404/487892認識到這些調試幻數可以幫助你在未來。 – drescherjm