有什麼辦法可以在SQL中結合LIKE和IN？

現在我有以下SQL：有什麼辦法可以在SQL中結合LIKE和IN？

select MAX(score) as score, title from 
(
select 2 as score, title from tableName WHERE title LIKE '%railway employee%' 
union 
select 1 as score, title from tableName WHERE title LIKE '%railway%' 
union 
select 1 as score, title from tableName WHERE title LIKE '%employee%' 
) as t1 
group by title 
order by score DESC

我希望能夠做這樣的事情：

select MAX(score) as score, title from 
(
select LEN(CurrentTerm) as score, title from tableName WHERE title LIKE IN ('%railway employee%', '%railway%', '%employee%') 
) as t1 
group by title 
order by score DESC

的CurrentTerm將是匹配的期限，而不是在表中的列。 SQL中有什麼甚至是遠程類似的東西，特別是MySQL？

來源

2013-06-20 Justin808

我想你可以使用正則表達式而不是'LIKE IN'。 –

根據查詢，數據庫中顯示缺少正常狀態。更好的數據庫結構可能是最佳解決方案。 –

不能使用LIKE IN但你可以使用OR：

select MAX(score) as score, title from 
(
    select LEN(CurrentTerm) as score, title 
    from tableName 
    WHERE title LIKE '%railway employee%' 
    OR title LIKE '%railway%' 
    OR title LIKE '%employee%' 
) as t1 
group by title 
order by score DESC;

您可能能夠使用類似於它使用3個搜索詞的派生表的得分值以下的東西：

select max(score) as score, title 
from 
(
    select 2 score, 'railway employee' term union all 
    select 1 score, 'railway' term union all 
    select 1 score, 'employee' term 
) d 
inner join tableName t 
    on title like concat('%', term, '%') 
group by title 
order by score desc;

見SQL Fiddle with Demo

來源

2013-06-20 21:16:44 Taryn

'LEN（CurrentTerm）'應該基於我認爲匹配的術語。因此，匹配'鐵路員工'的人得分高於那些匹配'鐵路'的人＃ –

@MartinSmith可能，這將有助於它在OP中澄清。 :) – Taryn

@bluefeet - 對不起。馬丁對我的意思是正確的。我已經更新了這個問題來指定'CurrentTerm'它是匹配項。 – Justin808

您可以通過使用or簡化查詢：

select MAX(score) as score, title 
from (select LEN(CurrentTerm) as score, title 
     from tableName 
     WHERE title LIKE '%railway employee%' or 
      title like '%railway%' or 
      title like '%employee%' 
    ) as t1 
group by title 
order by score DESC

編輯：

我明白了，你沒有「CurrentTerm」在數據庫中。這裏是一個更好的版本：

select max(case when title LIKE '%railway employee%' then 2 
       when title LIKE '%railway%' then 1 
       when title LIKE '%employee%' then 1 
      end) as score, title 
from tableName 
WHERE title like '%railway%' or title like '%employee%' 
group by title 
order by score DESC

其實是沒有必要的，但與原始查詢一致性的最終where。它不需要「％鐵路員工％」，因爲它符合兩者。

來源

2013-06-20 21:16:55

有什麼辦法可以在SQL中結合LIKE和IN？

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