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我想對每個時間戳的總和進行合計& Reasoncode。鑑於下面的示例代碼,它不起作用。你可以請幫我在做這個工作如何根據使用XSLT的2個元素進行求和
我的XML:
我已經使用了下面的XML作爲輸入文件
<?xml version="1.0" encoding="UTF-8"?>
<Earnings>
<Collection>
<Timestamp>20170101</Timestamp>
<Points>100</Points>
<ReasonCode>AN</ReasonCode>
</Collection>
<Collection>
<Timestamp>20170102</Timestamp>
<Points>100</Points>
<ReasonCode>AN</ReasonCode>
</Collection>
<Collection>
<Timestamp>20170101</Timestamp>
<Points>10000</Points>
<ReasonCode>BP</ReasonCode>
</Collection>
<Collection>
<Timestamp>20170101</Timestamp>
<Points>10000</Points>
<ReasonCode>BP</ReasonCode>
</Collection>
<Collection>
<Timestamp>20170102</Timestamp>
<Points>100</Points>
<ReasonCode>PPTS</ReasonCode>
</Collection>
</Earnings>
我的XSLT
我用用下面的XSLT我的XML轉換爲指定格式
<?xml version="1.0" encoding="UTF-16"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:key name="Earnings" match="Earnings/Collection" use="concat(Timestamp, '+',ReasonCode)"/>
<xsl:template match="Earnings">
<Earnings>
<xsl:for-each select="Collection[generate-id() = generate-id(key('Earnings', concat(Timestamp, '+',ReasonCode))[1])]">
<xsl:sort select="concat(Timestamp, '+',ReasonCode)"/>
<xsl:variable name="current-group" select="/Earnings/Collection[ReasonCode = current()/ReasonCode]"/>
<Collection>
<Timestamp>
<xsl:value-of select="Timestamp"/>
</Timestamp>
<Points>
<xsl:value-of select="sum($current-group/Points)"/>
</Points>
<ReasonCode>
<xsl:value-of select="ReasonCode"/>
</ReasonCode>
</Collection>
</xsl:for-each>
</Earnings>
</xsl:template>
</xsl:stylesheet>
的預期輸出
個<Collection>
<Timestamp>20170101</Timestamp>
<Points>100</Points>
<ReasonCode>AN</ReasonCode>
</Collection>
<Collection>
<Timestamp>20170101</Timestamp>
<Points>2000</Points>
<ReasonCode>BP</ReasonCode>
</Collection>
<Collection>
<Timestamp>20170102</Timestamp>
<Points>100</Points>
<ReasonCode>AN</ReasonCode>
</Collection>
<Collection>
<Timestamp>20170102</Timestamp>
<Points>100</Points>
<ReasonCode>PPTS</ReasonCode>
</Collection>
感謝,
磨憨
謝謝邁克爾。它的工作正常。 –