PHP的字符串替換難倒我

Question

這不是工作，這是怎麼回事，應該是這麼簡單:-(

$test = "hello naughty"; 


$swearWords = array("naughty","notallowed"); 

foreach ($swearWords as $naughty) 
{ 
    $post = str_ireplace($naughty, "<b><i>(oops)</i></b>", $test); 

} 

echo $post; 

感謝

Answer 1

你（總是）使用$測試作爲輸入參數。
在foreach循環的第二次迭代的針notallowed的例子中沒有找到，並且因此輸入字符串$test='hello naughty'原封不動地返回。

<?php 
$test = "hello naughty"; 
$swearWords = array("naughty","notallowed"); 

$post = $test; 
foreach ($swearWords as $naughty) 
{ 
    $post = str_ireplace($naughty, "<b><i>(oops)</i></b>", $post); 
} 

echo $post; 

個

打印hello <b><i>(oops)</i></b>

和str_ireplace可以採取針陣列作爲第一參數

<?php 
$test = "hello notallowed, this is naughty"; 
$post = str_ireplace(array("naughty","notallowed"), "<b><i>(oops)</i></b>", $test); 
echo $post; 

打印hello <b><i>(oops)</i></b>, this is <b><i>(oops)</i></b>。

Answer 2

$ swearWords = array（「naughty」）; 然後它說（哎呀）而不是淘氣。

Answer 3

您可以直接使用陣列更換

<?php 

    $test = "hello naughty"; 
    $swearWords = array("naughty","notallowed"); 
    $post = str_ireplace($swearWords, "<b><i>(oops)</i></b>", $test); 
    echo $post; 
?> 

Answer 4

使用

$test = "hello naughty"; 
$swearWords = array("naughty","notallowed"); 
$post = str_ireplace($swearWords,"<b><i>(oops)</i></b>",$test) 
echo $post; 

代替。有關函數處理數組參數的方式，請參閱str_ireplace。

Answer 5

嘗試用這種

$test = "hello naughty"; 


$swearWords = array("naughty","notallowed"); 

foreach ($swearWords as $naughty) 
{ 
//$post = str_ireplace($naughty, "(oops)", $test); 
echo str_ireplace($naughty,"<b><i>(oops)</i></b>",$test)."<br>"; 

} 

嘗試編輯的代碼

Answer 6

支持其他的答案我有幾個環節表示例來幫助你。

這些對你有幫助並解決你的問題。

http://www.w3schools.com/php/func_string_str_ireplace.asp

http://php.net/manual/en/function.str-ireplace.php

感謝。