MySQL數據庫查詢與if條件

Question

我有一個表名視頻

表視頻

id name upload_date 

1 one  1408336348 
2 two  1409884215 

現在我要選擇，如果上傳的最後2天之間的視頻，然後是所有的數據也計算或沒有

結果像

id name upload_date new 

1 one  1408336348 no 
2 two  1409884215 yes 

我使用這個查詢，但無法工作

SELECT v.*,(if(from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY) then 'no' else 'yes') 
AS new FROM `video` as v 

查詢返回錯誤

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') then 'no' else 'yes') 
AS new FROM `video` as v 
LIMIT 0, 25' at line 1 

Answer 1

嘗試使用情況

SELECT v.* 
    ,case 
     when (from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY) then 'yes' 
     else 'no') 
    end AS new 
FROM `video` as v 

Answer 2

這不是在一個MySQL的IF正確的語法。試着這樣說：

SELECT v.*, 
    IF(from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY, 'yes', 'no') AS new 
FROM `video` as v 

Answer 3

問案聲明：

SELECT v.*, 
    CASE WHEN from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY 
     THEN 'Yes' 
     ELSE 'No' 
    END AS new 
FROM `video` 

這是ANSI標準的方式做到這一點的SQL。