如何獲取Ruby中數組的最後一個元素？

Question

如何從數組中獲取數值，就像使用.map一樣？這裏是我的代碼：

counter = 0 
ary = Array.new 

puts "How many teams do you have to enter?" 
hm = gets.to_i 

until counter == hm do 
    puts "Team City" 
    city = gets.chomp 

    puts "Team Name" 
    team = gets.chomp 

    ary.push([city, team]) 
    counter += 1 
end 

ary.map { |x, y| 
    puts "City: #{x} | Team: #{y}" 
} 

print "The last team entered was: " 
ary.last 

最終的結果看起來是這樣的：

City: Boston | Team: Bruins 
City: Toronto | Team: Maple Leafs 
The last team entered was: 
=> ["Toronto", "Maple Leafs"] 

但我想最後一行讀

The last team entered was: Toronto Maple Leafs 

我如何獲得該行我的價值觀，而不=>括號和引號？

Answer 1

使用打印的，而不是看跌期權，當你不想要一個新行不字符在例如線的末端時獲取用戶輸入，此外還可以使用#{variable}使用放在同一行內進行打印：

counter = 0 
ary = Array.new 

print "How many teams do you have to enter? " 
hm = gets.to_i 

until counter == hm do 
    print "Team #{counter + 1} City: " 
    city = gets.chomp 

    print "Team #{counter + 1} Name: " 
    team = gets.chomp 

    ary.push([city, team]) 
    counter += 1 
end 

ary.map { |x, y| puts "City: #{x} | Team: #{y}" } 

puts "The last team entered was: #{ary.last.join(' ')}" 

實例應用：

How many teams do you have to enter? 2 
Team 1 City: Boston 
Team 1 Name: Bruins 
Team 2 City: Toronto 
Team 2 Name: Maple Leafs 
City: Boston | Team: Bruins 
City: Toronto | Team: Maple Leafs 
The last team entered was: Toronto Maple Leafs 

試試吧here!

Answer 2

基本上，你的問題是「如何加入字符串數組元素連接成一個字符串」，並Array#join就派上用場了：

["Toronto", "Maple Leafs"].join(' ') 
#⇒ "Toronto Maple Leafs" 

Answer 3

試試：

team_last = ary.last 
puts "The last team entered was:" + team_last[0] + team_last[1] 

Answer 4

的另一種方式與*：

puts ["Toronto", "Maple Leafs"] * ', ' 
#Toronto, Maple Leafs 
#=> nil 

但我不認爲任何人使用這個符號，從而在另一個答案中推薦使用join。

Answer 5

根據你的代碼ary.last本身返回數組所以首先你需要通過ary.last.join(' ')加入數組中的兩個元素，將其轉換爲字符串，然後你將與你的消息字符串插值它即"The last team entered was: #{ary.last.join(' ')}"

代碼的最後兩行會改變爲：

print "The last team entered was: #{ary.last.join(' ')}"