使用In從第二個查詢中提取結果

Question

我有一個存儲Invoice詳細信息的數據庫。正如您所期望的，發票的每個細節都列在數據庫中。一些樣本信息：

Invoice#  Service_Type Detail_Code 
1234   1    AB 
1234   2    DF 
1234   5    ER 
1235   1    AB 
1236   1    AB 
1236   2    DF 
1237   1    AB 
1238   1    AB 
1239   1    AB 
1239   3    DZ 

我想編寫一個查詢計算服務中，客戶有「1」的服務類型，並沒有DZ或DF的詳細信息代碼的數量。所以在這種情況下，我的查詢結果是：

"3" 

它將計數發票號碼：

1235 
1237 
1238 

我不太能拿到。這裏是我的查詢：

SELECT Invoice_Number 
FROM Invoice_Detail_Tb 
WHERE (Invoice_Number IN (SELECT Invoice_Number 
          FROM Invoice_Detail_Tb AS Invoice_Detail_Tb_1 
          WHERE (Service_type = '1') 
          AND (Invoice_Date BETWEEN @startdate AND @enddate) 
          AND (Store_Number = @storenumber))) 
    AND (Detail_Code NOT IN ('DF', 'DZ')) 

當我運行此查詢，我不斷地得到「6」，這是與SERVICE_TYPE「1」服務的總數。我錯過了什麼？

Answer 1

一種方法是使用EXCEPT。

SELECT Invoice_Number 
FROM Invoice_Detail_Tb 
where service_type = '1' 
EXCEPT 
SELECT Invoice_Number 
FROM Invoice_Detail_Tb 
where Detail_Code IN ('DF', 'DZ') 

因爲你不能使用except，您可以使用not exists。

SQL Fiddle

SELECT Invoice_Number --use count(*) if you only need count 
FROM Invoice_Detail_Tb t 
where service_type = '1' 
and not exists(select 1 from Invoice_Detail_Tb where invoice_number = t.invoice_number and 
       Detail_Code IN ('DF', 'DZ')) 

Answer 2

使用DISTINCT時，它可以是非常簡單的，獲得唯一的發票編號：

SELECT DISTINCT 
    Invoice_Number 
FROM Invoice_Detail_Tb 
WHERE 
    Service_type = '1' 
    and Detail_Code NOT IN ('DF', 'DZ') 
    and Invoice_Date BETWEEN @startdate AND @enddate 
    and Store_Number = @storenumber 

而對於計數服務：

SELECT 
    Invoice_Number, 
    count(*) as services_Count 
FROM Invoice_Detail_Tb 
WHERE 
    Service_type = '1' 
    and Detail_Code NOT IN ('DF', 'DZ') 
    and Invoice_Date BETWEEN @startdate AND @enddate 
    and Store_Number = @storenumber 
GROUP BY Invoice_Number