在sql中加入計數

Question

我對SQL很陌生，並且試圖做一些事情而不是愚蠢的方式。爲了給出一些背景，我正在比較運營商分支機構的規劃和實際使用情況，並且需要統計兩者的發生情況。我有一個with subquery as返回類似以下

PLANNED | REALIZED 
---------+---------- 
TRUCK | BI-TREM 
TRUCK | TRUCK 
TRUCK | TRUCK 
TRUCK | TRUCK 
TRUCK | TRUCK 
CARRETA | CARRETA 
CARRETA | CARRETA 
TRUCK | KOMBI 
TRUCK | BI-TREM 
CARRETA | KOMBI 
CARRETA | KOMBI 
TRUCK | TRUCK 
CARRETA | CARRETA 
CARRETA | BI-TREM 
CARRETA | CARRETA 
CARRETA | CARRETA 
TRUCK | BI-TREM 

，想返回類似以下

VEHICLE | TOTAL_PLANNED | TOTAL_REALIZED 
--------+---------------+--------------- 
CARRETA | 8    | 5 
TRUCK | 9    | 5 
BI-TREM | 0    | 4 
KOMBI | 0    | 3 

我已經試過以下

select PLANNED, 
     count(*) as TOTAL_PLANNED 
     null as REALIZED, 
     0 as TOTAL_REALIZED 
from subquery 
group by PLANNED 

union all 

select null as PLANNED, 
     0 as TOTAL_PLANNED, 
     REALIZED, 
     count(*) as TOTAL_REALIZED 
from subquery 
group by REALIZED 

返回

CARRETA 8 NULL 0 
TRUCK 9 NULL 0 
NULL 0 BI-TREM 4 
NULL 0 CARRETA 5 
NULL 0 TRUCK 5 
NULL 0 KOMBI 3 

我也嘗試了使用子查詢的所有可用連接，但沒有成功。事實上，RIGHT JOIN的作品，但只是因爲所有計劃的車輛也在實現方面：如果有一些沒有，我會在VEHICLE列有一個NULL。

感謝您的幫助，即使只是一個指向SQL命令的指針。

PS：這個查詢必須同時在SQL Server和Oracle上工作，所以我在努力爭取純SQL。

Answer 1

嘗試：

SELECT PLANNED_REALIZED AS VEHICLE, 
     SUM(TOTAL_PLANNED) AS TOTAL_PLANNED, 
     SUM(TOTAL_REALIZED) AS TOTAL_REALIZED 
FROM 
(select PLANNED AS PLANNED_REALIZED, 
     1 as TOTAL_PLANNED 
     0 as TOTAL_REALIZED 
from subquery 
union all 
select REALIZED as PLANNED_REALIZED, 
     0 as TOTAL_PLANNED, 
     1 as TOTAL_REALIZED 
from subquery 
) SQ 
GROUP BY PLANNED_REALIZED 

Answer 2

我認爲這應該工作：

select T.VEHICLE, 
     (SELECT count(*) FROM Table AS T1 WHERE T1.PLANNED = T.VEHICLE) AS TOTAL_PLANNED 
     (SELECT count(*) FROM Table AS T2 WHERE T2.REALIZED = T.VEHICLE) AS TOTAL_REALIZED, 
from (SELECT DISTINCT PLANNED AS VEHICLE FROM Table 
     UNION SELECT DISTINCT REALIZED AS VEHICLE FROM Table) AS T